To solve this problem we need to know the form of the general equation of the line. That is, y= mx+b where m is the slope and b is the intercept. We are already given the y-intercept (2) our next step is to fin the slope. Substitute the point give (1,1) in the equation y= mx+2 and then solve for m. The slope is then -6. The final equation is y = -x+2 or <span>x + y - 2 = 0</span>
Answer:
AB+BE+EF+GF+HG+AH = 14 #EQU 1
BC+CD+DE+EF+GF+BG = 22 #EQU 2
AB+BC+CD+DE+EF+GF+HG+AH = 24 #EQU 3
IMPLEMENTING EQU 2 IN EQU 3
AB+22-EF+ HG+AH = 24 # EQU 5
FROM EQU 1
AB+HG+AH = 14-(BE+EF+GF) #EQU 4
IMPLEMENTING EQU 4 IN EQU 5
22+14 - (BE+EF+GF+EF) = 24
36 - 24 = BE+EF+GF+BG(EF=BG)
12 = PATH TAKEN ON THURSDAY
They are both equal because in decimals you can add thousands of zeros and it's still equal.
Answer: She sold 6.6kg of pears in the market.
Step-by-step explanation:
Weight of apples and pears at the farmer's market.=8.8 kilograms
Weight of apples = 1/4
which is = 1/4 x 8.8kg = 2.2 kg
Weight of Pears =Weight of apples and pears - Weight of apples
= 8.8kg- 2.2kg
= 6.6kg