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Studentka2010 [4]
2 years ago
7

Reposting this because no body gave me the equation. An equation would be appreciated :)

Mathematics
2 answers:
Margaret [11]2 years ago
6 0

Answer:

\frac{6q}{5}  - 3 + 3 \leqslant 28 -  \frac{4q}{5}  + 3 \\  \\  \frac{6q}{5} \leqslant  -  \frac{4q}{5}   + 31 \\  \\  \frac{6q}{5}  +  \frac{4q}{5}  \leqslant  -  \frac{4q}{5}  +  \frac{4q}{5}  + 31 \\  \\  \frac{10q}{5}  \leqslant 31 \\  \\  2q \leqslant 31 \\  \\ 2q \div 2 \leqslant 31 \div 2 \\  \\ q \leqslant  \frac{31}{2}

I hope I helped you^_^

o-na [289]2 years ago
3 0

bring the like terms together,

\frac{6q}{5}  +  \frac{4q}{5}  \leqslant 28 + 3 + 3 - 3

\frac{10q}{5}  \leqslant 31

2q \leqslant 31

q \leqslant  \frac{31}{2}

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the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
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Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

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<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


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