40 drops of blood in a tube that holds 2 mL
HNO3 + Ca —-> H2O + N20 + Ca(NO3)2
6 electrons in total
2 on the first shell
4 on the second shell
Boron would have the lower first ionization energy.
Be: 1s2 2s2
B: 1s2 2s2 2p1 -> electron from the p orbital is easier to eject than than electron from the s orbital.
