When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now first write the balanced chemical equation
CuSO₄ (aq) + Na₂S (aq) → CuS(s) + Na₂SO₄ (aq)
Now write the net ionic equation
Cu⁺² (aq) + SO₄⁻² (aq) + 2Na⁺ (aq) + S⁻² (aq) → CuS (s) + 2Na⁺ + SO₄⁻² (aq)
So the net ionic equation is
Cu⁺² (aq) + S⁻² (aq) → CuS (s)
Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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Climatology is a subspecialty of Meterology.
Answer:
(a) A strong acid has a greater tendency to lose its protons.
(b) A strong acid has a higher Ka than a weak acid.
(c) A strong acid has a lower pKa than a weak acid.
Explanation:
A strong acid has the ability to completely transfer their protons to the water, making a complete dissociation. Instead, a weak acid only dissociates partially, how much it dissociates depends on the acid dissociation constant (Ka).
The weak acids always are in equilibrium, and the equilibrium depends on the acid dissociation constant.
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Thus, a stronger acid with a bigger Ka produces more dissociation and a higher concentration of protons.
The equation that defines pKa is:
Therefore, a higher pKa means a lower Ka and also a weaker acid.
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