<u>Answer:</u> The mass of bromine reacted is 160.6 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of aluminium = 18.1 g
Molar mass of aluminium = 27 g/mol
Putting values in equation 1, we get:

The chemical equation for the reaction of aluminium and bromide follows:

By Stoichiometry of the reaction:
2 moles of aluminium reacts with 3 moles of bromine gas
So, 0.670 moles of aluminium will react with =
of bromine gas.
Now, calculating the mass of bromine gas, we use equation 1:
Moles of bromine gas = 1.005 moles
Molar mass of bromine gas = 159.81 g/mol
Putting values in equation 1, we get:

Hence, the mass of bromine reacted is 160.6 grams.