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Sladkaya [172]
3 years ago
10

A medication 60 mg is ordered. the vial is labeled 1 gm/ 10 ml. How many ml would you give?

Chemistry
1 answer:
timofeeve [1]3 years ago
4 0
I believe it is 6ml because you do the doseage times the ml and mutiply it by 1
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Write a balanced chemical equation for the fermentation sucrose (C12H22O11) by yeasts in which the aqueous ethyl alcohol (C2H5OH
kodGreya [7K]

Answer:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)

Explanation:

When aqueous sugar (sucrose) react with water in the presence of yeast, the following products are obtained as shown in the equation below:

C12H22O11(aq) + H2O(l) —> C2H5OH(aq) + CO2(g)

Now, we shall balance the equation as follow:

There are a total of 24 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 4 in front of C2H5OH as shown below:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + CO2(g)

There are a total of 9 atoms of C on the right side and 12 atoms on the left side. It can be balance by putting 4 in front of CO2 as shown below:

C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)

Now the equation is balanced.

8 0
3 years ago
A chemist prepares a solution of calcium bromide CaBr2 by measuring out 4.81μmol of calcium bromide into a 50.mL volumetric flas
Mariana [72]

Answer:

The concentration of the CaBr2 solution is 96 µmol/L

Explanation:

<u>Step 1:</u> Data given

Moles of Calciumbromide (CaBr2) = 4.81 µmol

Volume of the flask = 50.0 mL = 0.05 L

<u>Step 2:</u> Calculate the concentration of Calciumbromide

Concentration CaBr2 = moles CaBr2 / volume

Concentration CaBr2 = 4.81 µmol / 0.05 L

Concentration CaBr2 = 96.2 µmol /L = 96.2 µM

The concentration of the CaBr2 solution is 96 µmol/L

4 0
3 years ago
Which type of bond will most likely be found in HBr?
NARA [144]
<span>HBr is covalent bond.!

</span>Hydrogen and Bromine will share their electrons, to obtain the electron configuration of a noble gas<span>.
</span>
hope this helps!

6 0
3 years ago
Read 2 more answers
the mass of one hydrogen atom is 1.67x10^-27 kg. A cylinder contains 3.01x10^23 hydrogen atoms. What is the mass of the hydrogen
VladimirAG [237]
Multiply 1.67x10^-27 by 3.01x10^23
5 0
3 years ago
How many grams of KCIO3 will be formed from 3.58g of KCI
blsea [12.9K]

Answer:

5 mols

Explanation:

7 0
3 years ago
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