If i am not mistake u can use -log[concentration of oh-] to find it
ie -log[6.4*10^-10]=9.19
0.164 g/L is the density of a sample of 1.00 mole of 
at 793mmhg and -9.00 degrees celcius.
<h3>What is density?</h3>
Density is the mass of a unit volume of a material substance. The formula for density is d = 
, where d is density, M is mass, and V is volume.
Given data:
n = 1.00 mole
P=793 mm hg =1.04342 atm
T=-9.00 degree celcius = -9.00 + 273= 264 K
V=?
Using Ideal Gas Law equation:
PV = n R T
R = gas constant = 0.082057 L-atm/(mol-K)
(1.04342 atm)(V) = 5 X 0.082057 L-atm/(mol-K) X 264 K
V = 103.67 Liters
Now calculate density:
Mole weight of = 1.00 mole
So, the mass of = 17.031 g
Density = 
Density = 
= 0.164 g/L
Hence, 0.164 g/L is the density of a sample of 1.00 mole of at 793mmhg and -9.00 degrees celcius.
Learn more about the density here:
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Answer:
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Explanation:
Answer:
Explanation:
1. Please provide the enthalpy info - I will work on it with the info
2.
i) Reaction a should be modified to match the number of S in equation:
2S + 2O2 -> 2SO2 deltaH = -370kJ
ii) Reaction b should be written reversely to match the reactants of SO2:
2SO2 + O2 -> 2SO3 deltaH = 256kJ
iii) Adding the equations together:
2S + 3O2 -> 2SO3
iv) Enthalpy of the combined reaction = -370+256 = -114kJ
It is negative so the reaction is exothermic.
In a typical double displacement reaction, you would have a total of two products (AB + CD —> AD + BC).
