What is the 92nd term of the arithmetic sequence 11,19,27

Mathematics

1 answer:

satela [25.4K]3 years ago

4 0

Answer: the 92nd term of the arithmetic sequence 739

Step-by-step explanation:

In an arithmetic sequence, consecutive terms differ by a common difference. The formula for determining the nth term of an arithmetic sequence is expressed as

an = a1 + (n - 1)d

Where

a1 represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 11

d = 19 - 11 = 8

n = 92

We want to determine the value of the 92nd term, a92. Therefore,

a92 = 11 + (92 - 1)8

a92 = 11 + 728

a92 = 739

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What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2

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A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

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