Hello!
We can write this as the system of equations below. We have boxes A, B, and C.
A+B+C=9
B=A+1
C=B+1
First of all we can plug our B and C values into the first equation and solve for A.
A+A+1+A+1+1=9
3a+3=9
3a=6
a=2
Now we can plug our a value into the other equations.
B=2+1
B=3
C=3+1
C=4
Therefore, there are 2 rocks in one box, three in another, and 4 in the last.
I hope this helps!
The answer is that (It’s 6.6)
To find the original price, you could use a variable to represent the original price in this equation;
Let p represent the original price
.70 × p=11.20
to solve this, we'd isolate the variable (p)
p=11.20 ÷.70
p=16
The original price was $16
Answer:
Step-by-step explanation:
Notice that the inputs {5, -8, -1, -5} are all different. So we can immediately conclude that this is a function.
If the inputs were {5, -8, -1, 5}, this would not be a function, as the same input value (5) would result in two different outputs.
