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sladkih [1.3K]
3 years ago
9

What is force of attraction ?​

Physics
1 answer:
Otrada [13]3 years ago
7 0

Answer

a force between two bodies, molecules, particles, or the like, that attracts each to the other. Gravity is the force of attraction between two bodies that have mass.

Explanation:

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In Fig.25-46,how much charge is stored on the parallel-plate capacitors by the 12.0 V battery? One is filled with air,and the ot
Fittoniya [83]

Answer:

Q=7.9\times 10^{-10}\ C

Explanation:

Given that

V= 12 V

K=3

d= 2 mm

Area=5.00 $ 10#3 m2

Assume that

$ = Multiple sign

# = Negative sign

A=5\times 10^{-3}\ m^2

We Capacitance given as

For air

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}

C_1=2.2\times 10^{-11}\ F

C_2=\dfrac{K\varepsilon _oA}{d}

C_2=\dfrac{3\times 8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}\ F

C_2=6.6\times 10^{-11}\ F

Net capacitance

C=C₁+C₂

C=8.8\times 10^{-11}\ F

We know that charge Q given as

Q= C V

Q=12\times 6.6\times 10^{-11}\ C

Q=7.9\times 10^{-10}\ C

6 0
3 years ago
The fact that light travels at 300,000 km/s is a consequence of
Tresset [83]
<span>The fact that light travels at 300,000 km/s is a consequence of Energy Conservation
The particle that move with that kind of speed creates energy way faster than the particle that don't. Which means that it would require less effort to produce the energy,</span>
6 0
4 years ago
The time it takes for one wavelength to pass a fixed point is known as:
laiz [17]
<span>The time it takes for one wavelength to pass a fixed point is known as PERIOD.

In fact, the period is defined as the time it takes a wave to make one complete oscillation: since the wavelength is the distance between two consecutive points of the wave with same shape, it means that the time it takes for one wavelength to pass a fixed point in space is exactly the period.</span>
3 0
4 years ago
A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from po
saul85 [17]

The location of the point F that partitions a line segment from D to E (\overline{DE}), that goes from <u>negative 4</u> to <u>positive 5,</u> into a 5:6 ratio is fifteen halves (option 4).  

We need to calculate the segment of the line DE to find the location of point F.

Since point D is located at <u>negative -4</u> and point E is at <u>positive 5</u>, we have:

\overline{DE} = E - D = 5 - (-4) = 9

Hence, the segment of the line DE (\overline{DE}) is 9.

Knowing that point F partitions the line segment from D to E (\overline{DE}) into a <u>5:6 ratio</u>, its location would be:

F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2}  

Therefore, the location of point F is fifteen halves (option 4).

Learn more about segments here:

  • brainly.com/question/24472171?referrer=searchResults
  • brainly.com/question/13270900?referrer=searchResults

       

I hope it helps you!

5 0
3 years ago
Read 2 more answers
Light from a laser (lambda= 406.192 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen
dsp73

Answer:

The spacing between the slits is    d = 0.00145m                

Explanation:

From the question we are told that

  The wavelength of the light is \lambda = 406.192nm = 406.192*10^{-9} m

   The distance of the slit from the screen is D = 5.937 \ m

    The number of bright fringe is n = 24

     The  length the fringes span is   L = 39.835 mm = \frac{39.835 }{1000} = 0.0398 m

The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as

             \beta  = \frac{\lambda D}{d}

Where d is  the distance between the  slits

            \beta is the fringe width which can also be evaluated as

                         \beta = \frac{L}{n}

Substituting values

                        \beta = \frac{0.0398}{24}

                          \beta = 1.660 *10^{-3}

Making d the subject of formula in the above equation

                d = \frac{\lambda D}{\beta }

Substituting values

                d = \frac{406.192 *10^{-9} * 5.937 }{1.660 *10^{-3}}

                    d = 0.00145m                

           

4 0
4 years ago
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