Question

A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from point D to point E. What is the location of point F, which partitions the directed line segment from D to E into a 5:6 ratio? Negative one-eleventh One-eleventh Two-fifteenths Fifteen-halves.

Answer 1

Answer:

The above answer is actually incorrect - the real answer is B. 1/11

Explanation:

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Answer 2

The location of the point F that partitions a line segment from D to E ($\overline{DE}$), that goes from negative 4 to positive 5, into a 5:6 ratio is fifteen halves (option 4).  

We need to calculate the segment of the line DE to find the location of point F.

Since point D is located at negative -4 and point E is at positive 5, we have:

$\overline{DE} = E - D = 5 - (-4) = 9$

Hence, the segment of the line DE ($\overline{DE}$) is 9.

Knowing that point F partitions the line segment from D to E ($\overline{DE}$) into a 5:6 ratio, its location would be:

$F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2}$  

Therefore, the location of point F is fifteen halves (option 4).

Learn more about segments here:

• brainly.com/question/24472171?referrer=searchResults

• brainly.com/question/13270900?referrer=searchResults

       

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