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andrezito [222]
3 years ago
14

Batman is fighting superman. He throws his 5 kg fist at superman with a speed of 9 m/s. Superman stops the punch with a force of

45,000 N. How much time did it take for batman's hand to stop moving?
Physics
2 answers:
bulgar [2K]3 years ago
4 0

Answer:

It took 1x10^{-3} seconds for batman's hand to stop moving.

Explanation:

Newton' s second law is defined as:

F = ma (1)

Where m is the mass and a is the acceleration.

But it is known that the acceleration is defined as follow by the kinematic equation that corresponds to a Uniformly Accelerated Rectilinear Motion.

a = \frac{v_{2}-v_{1}}{t} (2)

Where v_{2} is the final velocity and v_{1} is the initial velocity

The initial velocity of the fist will be zero (v_{1} = 0) since it starts from a state of rest.

Then, equation 2 can be replaced in equation 1

F = m\frac{v_{2}-v_{1}}{t}  (3)

Therefore, t can be isolated from equation 3

t = m\frac{v_{2}-v_{1}}{F} (4)

t = (5Kg)\frac{9m/s-0m/s}{45000Kg.m/s^{2}}

t = 1x10^{-3}s

Hence, it took 1x10^{-3} seconds for batman's hand to stop moving.

deff fn [24]3 years ago
4 0

Answer:

1 × 10^-3 s.

Explanation:

Given:

Mass = 5 kg

V = 9 m/s

Force = 45000 N

Using Newton's law,

Force = mass × acceleration

= (mass × velocity)/time

45000 = (5 × 9)/time

Time = 1 × 10^-3 s.

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An electric drill rated at 400 W is connected to a 240V power line. How much current does it draw?
disa [49]

Answer:

1.67 A

Explanation:

Given that,

→ Power (P) = 400 W

→ Potential difference (V) = 240 V

→ Current (I) = ?

The amount of current drawn will be,

→ P = V × I

→ I = P/V

→ I = 400/240

→ I = 1.66666666667

→ [ I = 1.67 A ]

Hence, the current drawn 1.67 A.

8 0
2 years ago
Read 2 more answers
The joule and the kilowatt-hour are both units of energy. 15 kw · h is equivalent to how many joules? answer in units of j.
choli [55]

The solution for the problem is:

1 Watt = 1 Joule per second 
1 Watt*second = 1 Joule 

a Kilowatt is 1,000 Watts 
an hour is 60 seconds times 60 minutes or 3,600 seconds 
a Kilowatt * hour is 1,000 Watts in 3,600 seconds 

15 W*h = 15,000 Watt*hour = 15,000 Watt * 3,600 seconds = 54,000,000 Watt*second 

54,000,000 Watt*second = ? Joules 
54,000,000 Joules / second = 54,000,000 Watts

3 0
3 years ago
How to measure the volume of a baseball bat ( need answers ASAP )
vaieri [72.5K]

<em>Measure the amount of water it displaces.</em>

This won't be easy, because the bat floats in water.  But I think you can get around that little problem like this:

-- Get some kind of a tank or tub that's big enough to hold the whole bat under water.

-- Get a heavy weight, like a big wrench or a small rock.  

-- Fill the tub almost to the tippy top with water.

-- Slip the heavy weight into the tub, slowly.  Some water will run over the top and out of the tub.  That's OK ... it's exactly what you want.  If NO water runs over the top, pour some more in, until it runs out and then stops.  You want the tub full to the brimmy rim with the rock at the bottom of it.

-- Take the heavy weight out of the tub.

-- Now set the tub into a bigger tub or a deep pan.  The next time it overflows and some water runs out of it, you'll need to catch that water and measure it.

-- Get a short piece of heavy string.  Tie the heavy weight to somewhere near the middle of the bat.

-- Slowly slide the bat into the water, with the rock tied to it.  The bat needs to go complete underwater.

-- Some more water will run over the top and out of the tub, and INTO the lower tub.  Wait until the overflow stops and everything settles down again.

-- Take the bat (tied to the weight) out of the tub.  Slowly and carefully, so that your hand or your arm doesn't make any MORE water run over and out.

-- Lift the upper tub out of the lower tub.

-- Take the lower tub, with the overflow water in it.  Using a kitchen measuring cup, or a saucepan or a bottle, or anything else with liquid amounts marked on it, measure how much water overflowed into the lower tub.

THAT amount is the volume of the bat.

You may have to do some units conversions.  Like if you need the volume of the bat in cm³ and you used measuring vessels marked in fluid ounces.  But you can find all those conversion factors with a search on Floogle.

8 0
2 years ago
All of the follow are ways of measuring volume execpt:
bogdanovich [222]
A). Scale.
You CAN measure volume with all the following except a scale.
6 0
3 years ago
Q.1- Find the distance travelled by a particle moving in a straight line with uniform acceleration, in the 10th unit of time.
Korolek [52]

Answer:

If the acceleration is constant, the movements equations are:

a(t) = A.

for the velocity we can integrate over time:

v(t) = A*t + v0

where v0 is a constant of integration (the initial velocity), for the distance traveled between t = 0 units and t = 10 units, we can solve the integral:

\int\limits^{10}_0 {A*t + v0} \, dt = ((A/2)10^2 + v0*10) = (A*50 + v0*10)

Where to obtain the actual distance you can replace the constant acceleration A and the initial velocity v0.

4 0
3 years ago
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