Question

how much pure antifreeze must be added to 12 gallons of 10% antifreeze to make 70% antifreeze solution

Answer 1

(0.10 x 12) + 1.00 y = .5 (12 + y)

1.2 + 1.00 y = 6 + .5 y

.5 y = 4.8

y = 9.6 gallons

The answer is D