Ask question

Ask question

All categories

3 years ago

13

B

1 answer:

den301095 [7]3 years ago

6 0

Answer:

since line segment BAE crosses line segment FAC angle BAC and angle FAE are vertical angles

You might be interested in

Find the value of (-4)(6)(-7)

Llana [10]

Answer: 168

Step-by-step explanation: When your faced with a longer problem that involves some multiplication of positives and negatives, make sure you work the problem carefully from left to right.

So the first thing we want to do here is to

multiply -4 by 6 and that gives us -24.

Now bring down the (-7) and we have -24 (-7) which is 168.

So our answer is 168.

8 0

3 years ago

Read 2 more answers

What are the coordinates of A?<br> (, )

ladessa [460]

(7,10) I believe because the format (x,y)

7 0

3 years ago

Read 2 more answers

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

4 years ago

Read 2 more answers

Use the laws of logarithms and the values given below to evaluate the logarithmic expression.

Sidana [21]

Answer:

c edge

Step-by-step explanation:

6 0

4 years ago

-3 (x + 10) <br><br> HELP<br> PLEASE

galben [10]

Answer:

−3X−30

Step-by-step explanation:

5 0

3 years ago