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2 years ago

Un empresario compró 1000 tabletas a $1500 cada una. Vendió 450 de ellas obteniendo una

Mathematics

1 answer:

marishachu [46]2 years ago

6 0

Answer:

Step-by-step explanation:

1000($1500(0.40)) = $600 000

450($1500(0.25)) = $168,750

600,000 - 168,750 = $431,250

$431,250 / 550 = 784.0909090... $784.09

$1500 + $784.09 = $2,284.09

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there are 75 students on the sapphire team and 1/5 of them are in the band . how many students are in band?

faltersainse [42]

Answer:

Step-by-step explanation:

75/5 = 15

This spilts the 75 students into 5 different groups and each one has 15 which is 1/5 of the students

6 0

1 year ago

BRAINLIST HEHEH HELP PWEASEC

natka813 [3]

Answer:

A. The amount per text message.

B. 16x x y = 3.20

Step-by-step explanation:

A. the amount per text message doesn't change, only the amount of times you message does.

B. (below)

X- The amount of messages sent.

Y- The amount of months.

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3 years ago

A 4 digit starts with 25. The next two digits are3 times the first 2 digits. This 4 digit number is multiplied by352. What is pr

Stella [2.4K]

1st two are 25, next two are three times that

so 3 x 25 = 75

so the four digit number is 2575

that is multiplied by 352

so 2575 x 352 = 906400

5 0

3 years ago

Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%

balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

$A=A_{o}e^{-0.0001211.t}$ (1)

Where:

$A$ is the final amount of Carbon- 14

$A_{o}=$ is the initial amount of Carbon- 14

$t$ is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 $A$ is $19\%=0.19$ , assuming the initial amount of Carbon-14 $A_{o}=$ is $100\%$ :

$A=0.19A_{o}$ (2)

This means: $\frac{A}{A_{o}}=0.19$ (2)

Now,finding $t$ from (1):

$\frac{A}{A_{o}}=e^{-0.0001211.t}$ (3)

Applying natural logarithm on both sides:

$ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})$ (4)

$ln(0.19)=-0.0001211.t$ (5)

$t=\frac{ln(0.19)}{-0.0001211}$ (6)

Finally:

$t=13713.717years$ This is the age of the paintings and the option that is nearest to this value is C. 13839 years

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2 years ago

Do yall know what x+x

bogdanovich [222]

Answer:

2x "hope this helps"

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers