Can you post the question
Correct answer: C) dispersion forces
Dispersion forces are the intermolecular forces of attraction present in all types of molecules. These are the weakest forces of attraction in which atoms of the molecule align in such a way that weak forces of attraction develop between electron cloud of one atom and the positively charged nucleus of the adjacent atom. This is referred to as induced dipole-induced dipole type of interaction. Therefore in dispersion forces temporary dipoles are developed due to constant motion of electrons that results in asymmetric electron distribution around the nucleus in an atom.
Answer:
Molecular formula => C₃H₈O₃
Explanation:
From the question given above, the following data were obtained:
Carbon (C) = 39.12%
Hydrogen (H) = 8.75%
Oxygen (O) = 51.12%
Molar mass of compound = 92.09 g/mol
Molecular formula =?
Next, we shall determine the empirical formula of the compound. This can be obtained as follow:
C = 39.12%
H = 8.75%
O = 51.12%
Divide by their molar mass
C = 39.12 / 12 = 3.26
H = 8.75 / 1 = 8.75
O = 51.12 / 16 = 3.195
Divide by the smallest
C = 3.26 / 3.195 = 1
H = 8.75 / 3.195 = 2.7
O = 3.195 / 3.195 = 1
Thus, the empirical formula is CH₂.₇O
Finally, we shall determine the molecular formula of the compound. This can be obtained as follow:
Empirical formula = CH₂.₇O
Molar mass of compound = 92.09 g/mol
Molecular formula =?
Molecular formula = Empirical formula × n
Molecular formula = [CH₂.₇O]ₙ
92.09 = [12 + (2.7×1) + 16] × n
92.09 = 30.7n
Divide both side by 30.7
n = 92.09 / 30.7
n = 3
Molecular formula = [CH₂.₇O]ₙ
Molecular formula = [CH₂.₇O]₃
Molecular formula = C₃H₈O₃
Answer:
Yes
Explanation:
1. Mass of 0.60 mol of AuCl₃
2. Mass of AuCl₃ in 750 mL
The solubility of AuCl₃ is 68 g/100 mL.
In 750 mL of water, you can dissolve
∴ Yes, 750 mL of water can dissolve 0.60 mol of AuCl₃.
The molar mass of vanadinite is 1416.27 g/mol. Looking at
the molecular formula we can see that there is 1 mole of Cl for every mole of
vanadinite. Therefore:
mass percent = [(1 mole Cl * 35.45 g/mol) / (1 mole
Pb5(VO4)3Cl * 1416.27 g/mol)] * 100%
<span>mass percent = 2.50%</span>