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nignag [31]
3 years ago
12

Calculate the mass of 6.9 moles of nitrous acid (HNO2). Explain the process or show your work by including all values used to de

termine the answer.
Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:- 324.3 grams.

Solution:-  We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.

Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .

For example, NO_2 has one nitrogen atom and one oxygen atom. So, the molar mass of this is = atomic mass of N + 2(atomic mass of O)

= 14 + 2(16)

= 14 + 32  

= 46 gram per mol

gram per mol is the unit of molar mass. So, the molar mass of NO_2 is 46 grams per mol.

Let's calculate the molar mass of nitrous acid using the same concept.

molar mass of [HNO_2 = 1 + 14 + 2(16)

= 1 + 14 + 32

= 47 grams per mol

Now, 6.9 moles of nitrous acid could easily be converted to grams as:

6.9molHNO_2(\frac{47g}{1mol})

= 324.3 g

Hence, the mass of 6.9 moles of nitrous acid is 324.3 grams.

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A gas is confined in a 0.3m diameter cylinder by a piston, on which rests a weight. The mass of the piston is 85 kg. The local a
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Explanation:

Force applied on the gas will be as follows.

                   F_{gas} = F_{atm} + (m + M) g

As,   F = pressure × area. Hence, calculate the forces as follows.

                  F_{gas} = pressure × area

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Substituting the calculated values into the above formula as follows.

                F_{gas} = F_{atm} + (m + M) g

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Weak electrolytes are those solutions which do not undergo complete dissociation when dissolved in water. The dissociation of weak electrolytes is given by a rightleft arrow.

Weak acids are those substances which dissociate partially to give H^+ ions when dissolved in water. Thus most of molecules remain unionized in solutions.

CH_3COOH\rightleftharpoons CH_3COO^-+H^+

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