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Gelneren [198K]
3 years ago
7

Which refers to the type of chemical bond that involves the transfer of electrons between atoms? O metallic O polar covalent Oio

nic O covalent​
Chemistry
2 answers:
Amanda [17]3 years ago
6 0

Answer:

Ionic bonding

Metal atom transfers electron(a) to non metal atom

Lilit [14]3 years ago
6 0

Answer:

C-

Ionic

Explanation:

Just did the quiz

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What enzyme is coded for in the chromosome of bacteria?
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The correct answer would be, "<span>D. beta-galactosidase".
As all the others are made in different organisms.

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You are throwing a pizza party for 15 people and figure that each person will eat 4 slices. You call the pizza place and learn t
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Answer:

15 people x 4 slices so you’ll need 60 pieces

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Explanation:

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A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percentage, the student measures out 5.84 grams o
julsineya [31]

Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

3 0
4 years ago
Who believed that a grain of sand could be divided indefinitely?
Ilya [14]

Answer:

Democritus

Explanation:

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Calculate the potential energy of a 25kg ball sitting 25m high
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