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natka813 [3]
2 years ago
12

Solve:

rac{2x-20}{3} =2x" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Evgen [1.6K]2 years ago
7 0

Answer:

x = - 5

Step-by-step explanation:

\frac{2x-20}{3} = 2x ( multiply both sides by 3 to clear the fraction )

2x - 20 = 6x ( subtract 2x from both sides )

- 20 = 4x ( divide both sides by 4 )

- 5 = x

You might be interested in
75 miles to 225 miles as a fraction in simplest form
Pie

Answer:

\frac{1}{3}

Step-by-step explanation:

When reducing a number to its lowest term you use the GCF of the denominator and numerator then divide using this number. :

\frac{75}{225} ÷\frac{75}{75} = \frac{1}{3}

The gcf of 75 and 225 is 75 so we divide both the numerator and denominator by 75.

HOPE THIS HELPED

5 0
2 years ago
Which valve is closest to 85% of 25
Papessa [141]

Answer:

<h2>21</h2>

Step-by-step explanation:

The value that is closest

to 85% of 25 is 21 because

85% of is 21.25 and rounding

21.25 to the whole number is 21.

<em>Hope this helps! <3</em>

7 0
2 years ago
6279÷4= could you help me with this problem
Feliz [49]

Answer:  1,569.75

Step-by-step explanation:

6279÷4=1,569.75

:)

7 0
2 years ago
Type the correct answer in the box. Write the standard form of the quadratic equation modeled by the points shown in the table b
White raven [17]
Y =ax² + bx +c

1) Point (0,7)

7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7

2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------> a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ----> -1=2a + b

4)  a+b= - 3, ----> b= -3 - a (substitute in the second equation)
    2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1, a =2

5) a+b= - 3
    2 + b = -3
b = -5

y=2x² - 5x + 7

8 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
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