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koban [17]
3 years ago
5

Someone help asay will make brainlest and will give 10 points if right

Mathematics
2 answers:
Flauer [41]3 years ago
6 0

Answer:

2/9 divide fully quote me though

Step-by-step explanation:

you divided 10 by 45 and the answer is 2/9

Zigmanuir [339]3 years ago
3 0
N= 10/45 = 10(0.2/45)
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Answer:

Check the attached image

4 0
2 years ago
The x-coordinates of a point that lies on the y-axis is positive.
lbvjy [14]

Answer:

This is never true.

the x-coordinates of a point that lies on the y-axis is 0.


4 0
4 years ago
The value of
marusya05 [52]

\large\underline{\sf{Solution-}}

We have to find out the value of the fraction.

<u>Let us assume that:</u>

\sf \longmapsto x =2 +   \dfrac{1}{2 +  \dfrac{1}{2 +  \dfrac{1}{2 + ... \infty} } }

<u>We can also write it as:</u>

\sf \longmapsto x =2 + \dfrac{1}{x}

\sf \longmapsto x =\dfrac{2x + 1}{x}

\sf \longmapsto  {x}^{2}  =2x + 1

\sf \longmapsto {x}^{2}  - 2x - 1 = 0

<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b =  - 2 \\ \sf c =  - 1 \end{cases}

<u>By quadratic formula:</u>

\sf \longmapsto x =  \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{8} }{2}

\sf \longmapsto x =  \dfrac{2 \pm2 \sqrt{2} }{2}

\sf \longmapsto x = 1 \pm\sqrt{2}

\sf \longmapsto x = \begin{cases} \sf 1  + \sqrt{2} \\ \sf 1 -  \sqrt{2}  \end{cases}

<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

\sf :\implies x = 1 + \sqrt{2}

So, the value of the fraction is 1 + √2.

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=5x%20%20%2B%2011%287x%20-%203" id="TexFormula1" title="5x + 11(7x - 3" alt="5x + 11(7x - 3"
Murljashka [212]

82x - 33 ✅

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

5x + 11(7x - 3) \\  = 5x + 77x - 33 \\  = 82x - 33

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

3 0
3 years ago
Find the length of the hypotenuse of a triangle if one of its legs is 11 cm long and its perimeter is 132 cm.
rodikova [14]

Answer:

1.)

132 cm - 11 cm = 121 cm

So let the hypotenuse be x and the other leg be (121 - x).

11^2 + (121 - x)^2 = x^2

121 + 121^2 - 121(2)x = 0

x = 1/2 + 121/2 = 61 cm

Step-by-step explanation: not sure if this is right or not

7 0
3 years ago
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