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qaws [65]
3 years ago
13

I WILL GIVE BRAINLIEST 50 POINTS Find x. Round your answer to the nearest tenth of a degree.

Mathematics
2 answers:
sveta [45]3 years ago
8 0

Answer:

c = 30.8 (nearest tenth)

Step-by-step explanation:

Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Given:

  • a = 21
  • b = 22.5

Substitute given values into the formula and solve for c:

⇒ 21² + 22.5² = c²

⇒ 947.25 = c²

⇒ c = ±√(947.25)

⇒ c = ±30.8 (nearest tenth)

As distance is positive, c = 30.8 (nearest tenth) only

Angelina_Jolie [31]3 years ago
3 0

#b

\\ \rm\rightarrowtail tan47=\dfrac{b}{21}

\\ \rm\rightarrowtail b=21tan47

\\ \rm\rightarrowtail b=22.5

#c

\\ \rm\rightarrowtail cos47=\dfrac{21}{c}

\\ \rm\rightarrowtail c=21/cos47

\\ \rm\rightarrowtail c=30.88

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120 oz for 12.99..
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Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

6 0
3 years ago
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