Answer:
The correct answer is b.Amplify the gene using PCR. Insert the gene into a plasmid vector. Transform the vector into the bacteria.
Explanation:
If I have a very small amount of gene for a fluorescent protein than the first step is to amplify the gene so that appropriate protein can be produced. PCR is the instrument that is used to amplify the protein.
So after amplification of the gene, the plasmid vector will be used in which the gene will be inserted because the plasmid vector is used to insert this gene in host cells where protein will be expressed.
The final step will be to transform bacteria with recombinant plasmid so that plasmid can make its copy and express a fluorescent protein in bulk.
The answer would be chromosomes
The right lung<span> has </span>both<span> more </span>lobes<span> and segments than the left. It is </span>divided into <span>three </span>lobes<span>, an upper, middle, and a lower, by </span>two<span> fissures, one oblique and one horizontal. The upper, horizontal fissure, separates the upper from the middle </span>lobe<span>.</span>
Answer:
25% heterozygous tall
Explanation:
If we take the F1 generation as parents and let them self-fertilise, we have 4 crosses.
The first one for homozygous tall, then we have 100% AA.
The second and third one for heterozygous tall and we have 25% AA, 50%Aa and 25%aa for each of them.
The last one would be for dwarf, and we'll have 100%aa.
Adding all of them, we'll have
AA = 100 + 25 + 25 = 150%
Aa = 50+50 = 100%
aa = 100 + 25 + 25 = 150%
as we had 4 crosses, so dividing the total percentages by 4, we'll have,
AA = 37.5%
Aa = 25%
aa = 37.5%
:. The percentage of heterozygous tall would be 25%.
Hope it helps:)