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2 years ago

1. Find the slope of the line.

Mathematics

1 answer:

bija089 [108]2 years ago

8 0

Answer:

1/2

Step-by-step explanation:

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3 years ago

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Hayden is comparing the regular attendance of two karate clubs he draws the following pie charts?

Gala2k [10]

Answer: A) B.

B) D.

C) D.

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2 years ago

Five minus 6 times a number is equal to -11 plus 2 times the number

zepelin [54]

Answer:

No its not equal

Step-by-step explanation:

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2 years ago

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

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3 years ago

I’m so dumb pls help

deff fn [24]

Answer:

Step-by-step explanation:

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3 years ago