<h3>Hello there!</h3>
This is a quite interesting problem.
Since it is normally unsolvable without the functions, the answer must lay somewhere in the examples given.
In this case, it lays in f(0).
Why would that be? Because anything times 0 is equal to 0.
In f(0), x is equal to 0, so a*x is therefore equal to 0.
Knowing that, the only thing that is left behind is, when you substitute in 0 for x:
16 = -(b*4)
Therefore, we can then solve to get:
-16 = b * 4
-4 = b
And now it's fairly simple to get a: just plug b into f(3) and solve.
25 = (3a) - (-4*4)
25 = 3a + 16
25 - 16 = 3a
9 = 3a
a = 3
And now to solve for what the question is looking for, just add a and b.
3 + -4 = -1
And there's your answer.
<h3>
a + b = -1</h3>
Answer:
3/4 times 18= 13.5
31.5-13.5=18
It cost 18 dollars for the skirt with a discount.
It cost 13.5 for the blouse as opposed to the original price of 18 dollars.
18(skirt)+13.5(blouse)=31.5
If you set up a proportion to find the original price of the skirt you will get the answer.
18/x=75/100
75x=18 times 100
75x=1800
75x/75=1800/75
x=24
The original price of the skirt is 24 dollars.
Step-by-step explanation:
2 will replace each x on the right
3•(2^3) - 4•(2^2) + 2 -1
3•8 - 4•4 + 1
24 - 16 + 1
8+1
9
Note that while the figure is made up of rectangle and parallelogram, then the area of this figure
![A_{figure}=A_{rectangle}+A_{parallelogram}.](https://tex.z-dn.net/?f=A_%7Bfigure%7D%3DA_%7Brectangle%7D%2BA_%7Bparallelogram%7D.)
1. The area of rectangle is
![A_{rectangle\ ABCF}=AB\cdot BC.](https://tex.z-dn.net/?f=A_%7Brectangle%5C%20ABCF%7D%3DAB%5Ccdot%20BC.)
The vertices of rectangle are points A(-2,-2), B(0,-6), C(8,-2) and F(6,2). Then
![AB=\sqrt{(-2-0)^2+(-2+6)^2}=\sqrt{4+16}=\sqrt{20}=2\sqrt{5},\\ \\BC=\sqrt{(8-0)^2+(-2+6)^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}.](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%28-2-0%29%5E2%2B%28-2%2B6%29%5E2%7D%3D%5Csqrt%7B4%2B16%7D%3D%5Csqrt%7B20%7D%3D2%5Csqrt%7B5%7D%2C%5C%5C%20%5C%5CBC%3D%5Csqrt%7B%288-0%29%5E2%2B%28-2%2B6%29%5E2%7D%3D%5Csqrt%7B64%2B16%7D%3D%5Csqrt%7B80%7D%3D4%5Csqrt%7B5%7D.)
Therefore,
![A_{rectangle\ ABCF}=2\sqrt{5}\cdot 4\sqrt{5}=8\cdot 5=40\ un.^2](https://tex.z-dn.net/?f=A_%7Brectangle%5C%20ABCF%7D%3D2%5Csqrt%7B5%7D%5Ccdot%204%5Csqrt%7B5%7D%3D8%5Ccdot%205%3D40%5C%20un.%5E2)
2. The area of parallelogram can be calculated using formula
![A_{parallelogram\ FCDE}=\text{base}\cdot \text{height}.](https://tex.z-dn.net/?f=A_%7Bparallelogram%5C%20FCDE%7D%3D%5Ctext%7Bbase%7D%5Ccdot%20%5Ctext%7Bheight%7D.)
The base of parallelogram is segment CD with length
and the height has length 2 un. Then
![A_{parallelogram\ FCDE}=5\cdot 2=10\ un^2.](https://tex.z-dn.net/?f=A_%7Bparallelogram%5C%20FCDE%7D%3D5%5Ccdot%202%3D10%5C%20un%5E2.)
3. Now
![A_{figure}=40+10=50\ un.^2](https://tex.z-dn.net/?f=A_%7Bfigure%7D%3D40%2B10%3D50%5C%20un.%5E2)
Answer:
100000000000000000000000000
Step-by-step explanation: