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gtnhenbr [62]
3 years ago
12

HELP ME WITH THIS! Plz

Mathematics
1 answer:
Lelu [443]3 years ago
6 0
It is 3 and 1/14ft or 3 and 4/16 ft taller
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What is the perimeter of the figure​
Natalija [7]

Answer:

The perimeter of the figure is 111.46 units

Step-by-step explanation:

Given:

RS = 43

LS = 18√2

A right Triangle is attached to a Rectangle.

A right Triangle is having measure angle 45° , 90°

and Hypotenuse = 18√2

∴ The Third Angle measure will also be 45° {angles Sum property of a triangle}

∴ the right angled triangle is an Isosceles triangle.

∴ Two sides are equal  LT = TS

To Find:

Perimeter of figure = ?

Solution:

we have

\sin 45 = \frac{\textrm{side opposite to angle 45}}{Hypotenuse}\\

we Know sin 45 = 1/√2

∴ \frac{1}{\sqrt{2} }= \frac{LT}{18\sqrt{2}}\\\\\therefore LT = 18\ unit\\\\\therefore TS = 18\ unit\\

Now ,

ARTL  is a Rectangle

∴ opposite side of a rectangle are equal

∴ LT = AR = 18 unit

and AL = RT

But,

RT = RS - TS

   = 43 - 18

   25

∴ AL = RT = 25

∴ Perimeter of figure = AL + LS + RS + AR

                                   = 25 + 18√2 + 43 + 18

                                   = 86 + 18√2

                                   = 111.455

                                   = 111.46 units

∴ Perimeter of figure = 111.46 units

7 0
3 years ago
Find the LCm for the pair of natural numbers <br> 112,96
n200080 [17]

Answer:

672.

Step-by-step explanation:

First find the prime factors:

112 = 2*2*2*2*7

96 = 2*2*2*2*2*3

There are 4 pairs of duplicate 2 's  in the factors, so the LCM = 2*2*2*2*2*3*7

= 672 (answer).

Note: the duplicates only appear once in the calculation of the LCM.

5 0
3 years ago
In a recent snail race,the winning snail traveled 5.85 cm 3/4 of a minute. How fast was the snail traveling in centimeters per s
Vladimir79 [104]

Answer:

0.121 centimeters per second.

Step-by-step explanation:    

We are told that in a recent snail race,the winning snail traveled 5.85 cm 3/4 of a minute.

To find the speed at which snail was traveling in centimeters per second, we will divide 5.85 by number of seconds in 3/4 of a minute.

First of all we will find how many seconds are equal to 3/4 of a minute.

\text{3/4 of a minute}=(\frac{3}{4} \times 60)\text{ seconds}

\text{3/4 of a minute}=3\times 15\text{ seconds}

\text{3/4 of a minute}=45\text{ seconds}

Now we will divide 5.85 by 45 to find the speed of snail in centimeters per second.

\text{Speed of snail in centimeters per second}=\frac{5.85\text{ Centimeters}}{45\text{ Second}}

\text{Speed of snail in centimeters per second}=0.1211111111111111\frac{\text{ Centimeters}}{\text{ Second}}

Therefore, the snail was traveling at a speed of 0.121 centimeters per second.

6 0
3 years ago
Read 2 more answers
REALLY URGENT. 1 3/5 divided by 2/5
Nikolay [14]

Answer:

4

Step-by-step explanation:

<em>1 3/5(2/5) = 4</em>

7 0
4 years ago
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Giving 15 points<br> SCATTER PLOT RELATIONSHIP
Alchen [17]

Answer:alla

Step-by-step explanation:

6 0
3 years ago
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