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Eva8 [605]
3 years ago
11

Solve 2-3x=-x-8 i need help on this question i cant solve this

Mathematics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

x=5

Step-by-step explanation:

We start by adding 3x to both sides, giving 2-3x+3x=-x+3x-8, which after simplifying gives 2=2x-8.

We then add 8 to both sides, giving 2+8=2x-8+8, which after simplifying gives 10=2x.

We can then divide both sides by 2, giving 10/2=2x/2, which after simplifying gives 5=x, or x=5. So, x is 5.

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(y+3):(y+5)=k:1<br><br> show that y=(5k-3)/(1-k)<br><br> hence y=(5k-2)/(1-k)
luda_lava [24]

hi,

Express the ratios in fractional form, that is

= ( cross- multiply )

y + 3 = k(y + 5) ← distribute

y + 3 = ky + 5k ( subtract ky from both sides )

y - ky + 3 = 5k ( subtract 3 from both sides )

y - ky = 5k - 3 ← factor out y from each term on the left side

y(1 - k) = 5k - 3 ← divide both sides by (1 - k)

y = 5k- 3

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1 - k

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Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5
Darina [25.2K]

Answer:

The consecutive numbers are 62 and 63

Step-by-step explanation:

Let the larger number be represented by x and the smaller number by y,

Provided they are consecutive numbers;

x = y + 1 --- Equation 1

From the question; we have that

\frac{4x}{7} = \frac{y}{2} + 5 --- Equation 2

Required

Find x and y

Multiply both sides of equation 2 by 14

14 * \frac{4x}{7} = 14 * \frac{y}{2} + 14 * 5

2 * 4x = 7 * y + 70

8x = 7y + 70 ---- Equation 3

Substitute y + 1 for x in equation 2

8(y + 1) = 7y + 70

Open bracket

8y + 8 = 7y + 70

Collect like terms

8y - 7y = 70 - 8

y = 62

x = y + 1

So,

x = 62 + 1

x = 63

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