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alexandr1967 [171]
3 years ago
7

Solve for n. 4(n-7)-(2-5n)=8n

Mathematics
2 answers:
damaskus [11]3 years ago
8 0
<h2><em><u>Question</u></em><em><u>;</u></em></h2>

<h2>4(n - 7) - (2 - 5n) = 8n</h2><h2><em><u>Solution</u></em><em><u>;</u></em></h2>

<h3>\begin{gathered}\\ \sf\longmapsto\end{gathered} Distribute 4 through the parentheses</h3>

<h2>4n - 28 - (2n - 5) = 8n</h2><h3>\begin{gathered}\\ \sf\longmapsto\end{gathered}When there is a - in front of an expression in parentheses, change the sign of each term in the expression</h3><h2 /><h2>4n - 28 - 2 + 5n = 8n</h2><h3>\begin{gathered}\\ \sf\longmapsto\end{gathered} collect like terms</h3>

<h2>9n - 28 - 2 = 8n</h2><h3>\begin{gathered}\\ \sf\longmapsto\end{gathered} Calculate the difference</h3>

<h2>9n - 30 = 8n</h2><h3>\begin{gathered}\\ \sf\longmapsto\end{gathered}Move the constant to the right-hand side and change its sign</h3>

<h2>&</h2>

<h3>\begin{gathered}\\ \sf\longmapsto\end{gathered}Move the variable to the left-hand side and change its sign</h3>

<h2>9n - 8n = 30</h2><h3>\begin{gathered}\\ \sf\longmapsto\end{gathered} Collect like terms</h3><h3 /><h2>n = 30</h2><h2>Solved ♤</h2>
Kisachek [45]3 years ago
4 0

Answer:

n = 30

Step-by-step explanation:

4(n - 7) - (2- 5n) = 8n ← distribute parenthesis on left side

4n - 28 - 2 + 5n = 8n

9n - 30 = 8n ( subtract 8n from both sides )

n - 30 = 0 ( add 30 to both sides )

n = 30

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Step-by-step explanation:

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3 years ago
Solve the equation. Show your work in the space provided. 2X - 0.5 = 3.7
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An oval track is made by erecting semicircles on each end of a 44 m by 88 m rectangle. Find the length of the track and the area
Dmitry_Shevchenko [17]

Answer:

The length of the track is 247 m.

The area enclosed by the track is  5391 . 76 sq m.

Step-by-step explanation:

The length of the rectangle  = 88 m

The width of the rectangle  =  44 m

Now, as we know the semicircles are at the end of rectangular track.

So, the diameter of semicircles = Width of the rectangle

⇒ The diameter of the semi circle  = 44 m

⇒Radius of the semi circle  = 44/2 = 22 m

TOTAL LENGTH OF TRACK  

= 2 ( Length of rectangle)  + 2 (Circumference of 1 semicircle)

= 2 x (88 m)  + 2 (\frac{2\pi r}{2})

= 176 m + 2 (3.14)(22 m)  = 176 + 71.08 =  247 m

Hence, the length of the track is 247 m

TOTAL AREA OF TRACK  

= (Area of rectangle)  + 2 (Area of 1 semicircle)

= (Length x Width)  +    2 (\frac{\pi r^2}{2})

=  (44  m x 88 m) +  (3.14)(22 m)(22 m)   = (3872  + 1519.76) sq m

=  5391 . 76 sq m

Hence, the area enclosed by the track is  5391 . 76 sq m.

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