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irga5000 [103]
3 years ago
6

I need help in math plz?​

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

1.A

2.A

3.C

4.D

5.A

6.A

7.D

8.B

9.A

10.C

Step-by-step explanation:

PA BRINLY TEST PLSSS

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Give the standard form 80,000+200+2
alexdok [17]

Answer:

80,202 = 8.0202 × 10⁴

5 0
2 years ago
Me need help what is this
Alex777 [14]
5 * 12 = 60 (for the whole area)
3 * 2 = 6 (for the missing space)
6 + 2 = 8
12 - 8 = 4
4 * 3 = 12
12 / 2 = 6
6 + 6 = 12
60 - 12 = 48
Answer: 48
Sorry if this isn’t right :(
8 0
3 years ago
Read 2 more answers
1. Consider a lottery with three possible outcomes:-$125 will be received with probability 0.2-$100 will be received with probab
Norma-Jean [14]

Answer:

The expected value of the lottery is $80

Step-by-step explanation:

To get the expected value, we have to multiply each outcome by its probability

Then we proceed to add up all of these to get the expected value of the lottery

we have this as ;;

125(0.2) + 100(0.3) + 50(0.5)

= 25 + 30 + 25 = $80

3 0
3 years ago
2/3 cup of sugar for 24 cookies equal how many cup in 1 cookie?
sweet [91]

Answer:

0.02777777777

Step-by-step explanation: 2/3 divided by 24 = 0.02777777777

5 0
3 years ago
A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 33.9 wee
MArishka [77]

Answer:

P(35.3 < M < 35.4) = 0.0040.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 33.9, \sigma = 6.7, n = 119, s = \frac{6.7}{\sqrt{119}} = 0.6142

Find the probability that a single randomly selected value is between 35.3 and 35.4

This is the pvalue of Z when X = 35.4 subtracted by the pvalue of Z when X = 35.3. So

X = 35.4

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{35.4 - 33.9}{0.6142}

Z = 2.44

Z = 2.44 has a pvalue of 0.9927

X = 35.3

Z = \frac{X - \mu}{s}

Z = \frac{35.3 - 33.9}{0.6142}

Z = 2.28

Z = 2.28 has a pvalue of 0.9887

0.9927 - 0.9887 = 0.0040

So the answer is:

P(35.3 < M < 35.4) = 0.0040.

4 0
4 years ago
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