1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irga5000 [103]
3 years ago
6

I need help in math plz?​

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

1.A

2.A

3.C

4.D

5.A

6.A

7.D

8.B

9.A

10.C

Step-by-step explanation:

PA BRINLY TEST PLSSS

You might be interested in
Rewrite the expression (x2 – 3x – 18)/(x – 9) using the long division method.
nadezda [96]

Answer:

<em>x + 3</em>

Step-by-step explanation:

<em>Image below</em>

7 0
3 years ago
Which of the following angles can be trisected using only a compass and straightedge?
ZanzabumX [31]
I'm pretty sure it is C. 45 because compass and straightedge is a right angle or an acute angle and 45 is less than a right angle
6 0
4 years ago
2 + 6x = 1 - X<br> Please help
Fynjy0 [20]

Answer:

-1/7

Step-by-step explanation:

The first step is to isolate the variable, x. To do so, add x to both sides. This gives you the new equation: 2 + 7x = 1.

Now, subtract 2 from both sides to further isolate the variable, giving you 7x = -1.

Divide both sides by 7, giving you the final equation of x = -1/7.

5 0
3 years ago
The system of equations below has no solution.
mixer [17]

Answer:

  • Second option: 0 = 26

Explanation:

This is the given system of equations:

\frac{2}{3} x+\frac{5}{2} y=15\\ \\ 4x+15y=12

A linear combination of the system is any equation formed by the algebraic addition of both equations, one or both multiplied by an arbitrary constant.

To prove that the given system has no solution you could multiply the first equation times 6 (to get rid of the fractions), multiply the second equation times - 1, and add the two results:

<u>1. First equation times 6:</u>

6\times\frac{2}{3} x+6\times\frac{5}{2}y=6\times 15\\ \\ 4x+15y=90

<u />

<u>2. Second equation times - 1:</u>

-4x-15y=-12

<u />

<u>3. Add the two new equations:</u>

0=78

<u />

<u>4. Conclusion:</u>

Since 0 = 78 is false, no matter what the value of x and y are, the conclusion is that the system of equations has not solution.

The only choice that represents that same situation is the second one, 0 = 26. That is a possible linear combination that represents that the system of equations has no solutions.

In fact, you might calculate the exact factors by which you had to multiply each one of the original equations to get 0 = 26, but it is not necessary to tell that that option represents a possible linear combination for the given system of equations.

7 0
3 years ago
Read 2 more answers
X/9+2x/2=1/3<br> X = ? <br> How to solve
Bas_tet [7]
X+9x=3

10x=3

The answer is x=3/10

3 0
4 years ago
Other questions:
  • which of the numbers 28 33 45 57 39 and 36 could be subtracted from 84 without regrouping? please explain
    7·2 answers
  • Cole is an urban planner. He wants to create a small scale drawing of a city block. The block is a square with sides of length 1
    14·2 answers
  • Dorji thought of a number. He first multiplied the number by 3 and then subtracted 12
    8·1 answer
  • Solve the system of linear equations.<br> x = 8 - 2y<br> x + 3y = 12
    9·1 answer
  • The sum of four consecutive integers is -26. What are the integers
    8·1 answer
  • Find the perimeter.<br> 8 cm<br> 34 cm<br> 23 cm<br> 49 cm
    5·2 answers
  • Explain how to find the area of the composite figure below. Be as specific as possible, using the formulas provided. [A=bh, A=lw
    13·1 answer
  • Suppose you want to buy bouquets of flowers for a party. An equation that represents the cost, y, in dollars, for x bouquets is
    10·1 answer
  • Multiply the polynomials.<br> (3x+4x+ 4)(2x - 4)
    10·1 answer
  • Heyy pls help with these math questions answer all and pls hurry thanks soo much
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!