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Oxana [17]
4 years ago
8

Can someone help me please

Mathematics
1 answer:
NikAS [45]4 years ago
6 0
Justin rides 550 kilometers
or
justin rides 17 meter
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The faces of a number cube are labeled 1 through 6. If the number cube is rolled 72 times, which is closest to the number of tim
insens350 [35]

Answer:

24 times

Step-by-step explanation:

P(5 or 6) = 2/6

2/6 = x/72

cross-multiply:

6x = 144

x = 24

4 0
3 years ago
2. 8 - 6x = 18x <br>I need help please ​
san4es73 [151]

Answer:

x=3

Step-by-step explanation:

8-6x=18x

8-6x+6x=18x+6x

8=24x

x=3

8 0
3 years ago
Read 2 more answers
What is the factored form of x2 – x – 2?
o-na [289]
(X-2)(x+1)

The first one












6 0
3 years ago
Read 2 more answers
Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).
lys-0071 [83]

Answer:

(x+1)^2 + (y- 3.5)^2 =64

Step-by-step explanation:

We are given that  endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

Substitute the values in formula

x=\frac{7-9}{2} , y=\frac{2+5}{2}

x=-1 , y=3.5

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

d=\sqrt{(-9-7)^2+(5-2)^2}

d=\sqrt{265}

Length of radius = r = \frac{Diameter}{2}=\frac{\sqrt{256}}{2}

Standard form of the equation of the circle : (x -h)^2 + (y- k)^2 = r^2

(h,k )=(-1,3.5)

r=\frac{\sqrt{256}}{2}

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =64

Hence  the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is  (x+1)^2 + (y- 3.5)^2 =64

5 0
4 years ago
Elyria Warehousing desired to locate a central warehouse to serve five Ohio markets. Placed on a grid system, its five markets h
Iteru [2.4K]

Answer:

The correct option is 2.

Step-by-step explanation:

According to the the center-of-gravity technique, the coordinates of the center-of-gravity location are

(\frac{\sum x_iL_i}{\sum L_i},\frac{\sum y_iL_i}{\sum L_i})

Where ((x_i,y_i) represent the coordinates and L_i is demand.

We have to find the Y-coordinate of the center-of-gravity location.

The sum of product of demand and corresponding y coordinates is

\sum y_iL_i=65\times 2200+55\times 900+95\times 1300+200\times 1750+175\times 3100=1208500

The sum of demanded units is

\sum L_i=2200+900+1300+1750+3100=9250

The Y-coordinate of the center-of-gravity location is

y_0=\frac{\sum y_iL_i}{\sum L_i}

y_0=\frac{1208500}{9250}

y_0=130.6486

y_0\approx 131

The Y-coordinate of the center-of-gravity location is 131. Therefore the correct option is 2.

7 0
3 years ago
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