Answer:
The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2
The rule of arithmetic sequence = a + d(n - 1)
Where a is the first term and n is the number of terms
So, for the even numbers between 0 and X
The first term = a = 0
d = 2
So, we need to find n at the last term which is X
∴ X = 0 + 2 ( n -1 )
∴ n - 1 = X/2
∴ n = X/2 + 1
The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)
Substitute with a and d and X
So, the sum = (n/2) * (2*0 + (n−1)*2)
= (n/2) * ((n−1)*2)
= n(n-1)
= (X/2 + 1) * (X/2)
= X/2 by (X/2 + 1)
So, The quick way to add all even numbers between 0 and X always works.
Partial products are the products obtained during the intermediate stages in order to complete a multiplication process.
Consider 68 
43, we have to determine the partial products in this.
Now, 
Expanding this, we get
= 
= 2400 + 180 + 320 + 24
= 2924
Hence, 
and 
are the required partial products in the product of 68 and 43.
So, Option 3 and 4 are the correct answers.
Answer:
V = 150.72 cm³.
Step-by-step explanation:
First, get the volume of a cylinder.
V = πr²h
Where:
π = 3.14 (given)
r = radius (half of diameter, or 2)
h = height (12)
Knowing this, substitute the known values.
V = πr²h
V = (3.14)(2²)(12)
Square 2.
V = (3.14)(4)(12)
Multiply 3.14 and 4.
V = (12.56)(12)
Multiply 12.56 and 12.
V = 150.72.
Since it is already rounded to the nearest hundredth, that is your answer.
