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sineoko [7]
3 years ago
7

Help, I have till today to turn these questions in. I will mark as brainliest, will be worth 40 points

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0
Hdjdxjjszjjsbejsbebs
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Fill in the blank with a constant, so that the resulting quadratic expression is the square of a binomial. $\[x^2 + 22x + \under
saw5 [17]

Answer:

$\[x^2 + 22x + 121\]$

Step-by-step explanation:

Given

$\[x^2 + 22x + \underline{~~~~}.\]$

Required

Fill in the gap

Represent the blank with k

$\[x^2 + 22x + k\]$

Solving for k...

To do this, we start by getting the coefficient of x

Coefficient of x = 22

<em />

Divide the coefficient by 2

Result = 22/2

Result = 11

Take the square of this result, to give k

k= 11^2

k= 121

Substitute 121 for k

$\[x^2 + 22x + 121\]$

The expression can be factorized as follows;

x^2 + 11x + 11x + 121

x(x + 11)+11(x+11)

(x+11)(x+11)

(x+11)^2

<em>Hence, the quadratic expression is </em>$\[x^2 + 22x + 121\]$<em></em>

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6m+12 = 2(2m+8) I need help
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