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sineoko [7]
3 years ago
7

Help, I have till today to turn these questions in. I will mark as brainliest, will be worth 40 points

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0
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The length of a rectangular garden is 30 yards more than the width. The perimeter is 300 yards. Find the length and width
Delicious77 [7]

Answer:

Length is 90yards and width is 60yards

Step-by-step explanation:

Perimeter= 2( length+width)

let the width be x

then the length will be 30 + x

300 = 2(30+x+x)

150 = 30 + 2x

120= 2x

x = 120/2

x = 60 yards

length= 30+x

= 30 + 60

= 90yards

8 0
2 years ago
How to find 2 equivalent fractions for 8/l0
Harlamova29_29 [7]

Answer:

4/5 ;$;$&$&&$&$*$,$*$,**$*$*$*$*$

4 0
3 years ago
Read 2 more answers
4x² = 32 What does x equal
babymother [125]

So here is what you would do:

lets just pretend that there is no x in the equation

so this is what the equation would look like:

first, is 4 to the power of 2=16 and now we are going to put the x back into the equation so: 4x to the power of 2, but we did the exponents so, now x is the missing number. We can use the 32 because it is the solution to the equation. So we would do 32-16=16 so the missing number is 16 so x=16

Answer: x=16

4 0
3 years ago
I need help ASEP please help me
Arisa [49]

Answer:

5

Step-by-step explanation:

it is 5 because you do 1+4=5

6 0
3 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
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