Look at!!:
Pre image A(3,4), B(1,5) C(6,6);
If you multiply these coordinates by 3/2, you get its images:
A(3,4) ⇒ A`(3*3/2, 4*3/2)=(4.5, 6)
B(1,5) ⇒B`(1.*3/2, 5*3/2)=(1.5, 7.5)
C(6,6) ⇒C`(6*3/2, 6*3/2)=(9,9)
Therefore the scale factor is 3/2.
When the scale factor of a dilation is >1, then we have an enlargement, an expansion.
In this case 3/2=1.5>1
Answer:
The dilation is expansion.
The scale factor is 3/2.
Answer:
Step-by-step explanation:
Because MK is a diameter, then angle L is a right angle. We already know that the measure of angle K is 50, so the measure of angle M has to be 40 because of the triangle angle-sum theorem. The rule for inscribed angles and the arcs they cut off is that the angle is half the measure of its intercepted arc or, likewise, the arc is twice the measure of the angle that cuts it off. Since arc LK is across from angle M and is cut off by angle M, then arc LK is twice the measure of angle M, and is 80. That's the same reason why angle L is 90; arc MK is a semi-circle, with a degree measure of 180, and angle L is half of that.
Arc LK = 80
Answer:
The coordinates of the midpoint of LN are 
answer (4)
Step-by-step explanation:
* Lets explain how to find the midpoint of a line
- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)
and (x2 , y2) are 
∵ LMNO is a square
∵ The coordinates of point L are (-6 , 1)
∵ The coordinates of point N are (1 , 8)
- Let the coordinates of point L are (x1 , y1) , the coordinates of point
N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)
∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8
- Use the rule of the midpoint above to find the midpoint (x , y)
∵ 
∵ 
∴ The coordinates of the midpoint are
* The coordinates of the midpoint of LN are
