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Alik [6]
3 years ago
6

Do I use LCM or HCF? And how can I decide which to use? (Brainliest if you can answer the whole thing)

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

As far as i know you should go for LCM that would be more convenient and easy to do

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Point A is located at (-6, 2). Which point on the coordinate plane shows a reflection of point A across the
Mrrafil [7]
I think (-6,-2) because it would switch into the all negative quadrant making them both negative.
3 0
3 years ago
Given klmn is a trapezoid, kl = mn, m<1 = m<2, lm/kn = 8/9, pklmn = 132. Find: the length of the legs
Ilia_Sergeevich [38]

Answer:

The length of legs lm, mn, and lk is 32 while that of kn is 36.

Step-by-step explanation:

The diagram is attached in the answer.

As both the angles are equal thus the two forms isosceles triangles. This is true because the converse of base angle theorem is applicable here. The theorem clearly states that when a trapezoid is divided by the diagonal, it forms two set of angles where m<1=m<2 and m<lmk=m<nmk

This leads the two set of legs such as

\dfrac{lm}{kn}=\dfrac{8}{9}

Or this could be written as

lm=8x\\kn=9x

Now the remaining two sides are given as

lk=lm as this form an isosceles triangle so

lk=8x

Similarly

mn=lm\\

Or

mn=8x

Now the perimeter is given as

\text{perimeter}=lm+mn+kn+lk\\

Here perimeter is given as 132 so this gives:

\text{perimeter}=lm+mn+kn+lk\\132=8x+8x+8x+9x\\132=33x\\x=\dfrac{132}{33}\\x=4

So the four legs are of length as given below:

lm=8x=8\times 4=32\\mn=8x=8\times 4=32\\lk=8x=8\times 4=32\\kn=9x=9\times4=36

So the length of legs lm, mn, and lk is 32 while that of kn is 36.

6 0
2 years ago
Solve −3x2 + 30x − 90 = 0. x equals 5 plus or minus 2i square root of 5 x equals 5 plus or minus i square root of 5 x equals 10
Tcecarenko [31]
The x in your equation is 16/5 or 3 1/5 or 3.2 if you want it simplified 
5 0
3 years ago
Read 2 more answers
Can somebody please help
sdas [7]

Answer:

next row in the x column = 8

next row in the y column  = 15

Step-by-step explanation:

7 0
3 years ago
Use the quadratic formula to solve 2^2 − 5 − 5 = 0<br> The formula is : ( -b ± √b^2 - 4ac ) / 2a
Serggg [28]

Answer:

x = 5/4 + √65/4 or x = 5/4 - √65/4

Step-by-step explanation:

I'm assuming you mean 2x^2-5x-5=0?

x = ( -b ± √b^2 - 4ac ) / 2a

x = ( -(-5) ± √(-5)^2 - 4(2)(-5) ) / 2(2)

x = ( 5 ± √(25 + 40) ) / 4

x = ( 5 ± √65 ) / 4

x = 5/4 ± √65/4

Therefore, x = 5/4 + √65/4 or x = 5/4 - √65/4

8 0
3 years ago
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