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3 years ago

The Nucleus of the Atom is in the center of the Atom, not in the outer rings & orbitals.

Physics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

true

Explanation:

this the nucleus is located at the centre and contains protons and neutrons

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Two billiard balls (each with mass equal to 170 g) collide head-on along the same line. Billiard ball A originally traveled east

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2 years ago

The mean distance of an asteroid from the Sun is 2.98 times that of Earth from the Sun. From Kepler's law of periods, calculate

lutik1710 [3]

Answer:

The asteroid requires 5.14 years to make one revolution around the Sun.

Explanation:

Kepler's third law establishes that the square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit:

$T^{2} = a^{3}$ (1)

Where T is the period of revolution and a is the semi-major axis.

In the other hand, the distance between the Earth and the Sun has a value of $1.50x10^{8} Km$ . That value can be known as well as an astronomical unit (1AU).

But 1 year is equivalent to 1 AU according with Kepler's third law, since 1 year is the orbital period of the Earth.

For the special case of the asteroid the distance will be:

$a = 2.98(1.50x10^{8}Km)$

$a = 4.47x10^{8}Km$

That distance will be expressed in terms of astronomical units:

$4.47x10^{8}Km.\frac{1AU}{1.50x10^{8}Km}$ ⇒ $2.98AU$

Finally, from equation 1 the period T can be isolated:

$T = \sqrt{a^{3}}$

$T = \sqrt{(2.98)^{3}}$

$T = \sqrt{26.463592}$

$T = 5.14AU$

Then, the period can be expressed in years:

$5.14AU.\frac{1yr}{1AU} ⇒ 5.14 yr$

$T = 5.14 yr$

Hence, the asteroid requires 5.14 years to make one revolution around the Sun.

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3 years ago

Conversion of one form of energy into another form is

Artist 52 [7]

Answer: energy transformation

5 0

2 years ago

Read 2 more answers

An 1,840 W toaster, a 1,460 W electric frying pan, and a 50 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (T

shutvik [7]

Answer:

Explanation:

Given

Power drawn by toaster $P_1=1840\ W$

Power drawn by Electric fan $P_2=1460\ W$

Power drawn by lamp $P_3=50\ W$

Voltage applied $V=120\ V$

If appliances are applied in parallel then Voltage applied is same

Power is given by $P=\frac{V^2}{R}$

Resistance of toaster $R_1=\frac{120^2}{1840}=7.82\ \Omega$

Resistance of electric Fan $R_2=\frac{120^2}{1460}=9.86\ \Omega$

Resistance of toaster $R_3=\frac{120^2}{50}=288\ \Omega$

Current is given by

$I=\frac{V}{R}$

$I_1=\frac{120}{7.82}=15.34\ A$

$I_2=\frac{120}{9.86}=12.17\ A$

$I_3=\frac{120}{288}=0.416\ A$

7 0

3 years ago

Read 2 more answers