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3 years ago

Solve by substitution. 5x-3y=-4 x+y=-4

Mathematics

1 answer:

GrogVix [38]3 years ago

5 0

Answer:

x=-2,y=-2

Step-by-step explanation:

x+y=-4

x=-4-y--(3)

substitute (3) in (1)

5(-4-y) -3y=-4

-20-5y-3y=-4

-8y=16

y=16/-8

y=-2

substitute y in (3)

x=-4-(-2)

x=-2

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3 years ago

Which expression has the same value as –y^–4?

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Answer is b

–y^–4 = – 1/y^4

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3 years ago

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A carpenter is framing a wall that is 8 feet high and 15 feet long. If the carpenter wants to be sure that the sides of the wall

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If you cut the rectangle (the wall) diagonally, you get two congruent triangles. The measurements of the sides of one the triangles is 8, 15 and x. There is a pythagorean triples 8, 15, 17 so x has to be 17. if you dont know the triple you can do a^2 + b^2 = c^2 8^2 + 15^2 = c^2 c = 17

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Find a vector function, r(t), that represents the curve of intersection of the two surfaces. The paraboloid z = 6x2 + y2 and the

LenKa [72]

Answer:

$\mathbf{r^{\to} (t) = ti^{\to} + 5t^2^{\to} j+(6t^2 + 25t^4) k ^{\to}}$

Step-by-step explanation:

Given that:

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Let assume that:

x = t

then from y = 5x², we have:

y = 5t²

Now replace y = 5t² and x = t into z = 6x² + y²

z = 6t² + (5t²)²

z = 6t² + 25t⁴

Hence, the curve of intersection is illustrated by the set of equations:

x = t, y = 5t², and z = 6t² + 25t⁴

As a vector equation:

$\mathbf{r^{\to} (t) = ti^{\to} + 5t^2^{\to} j+(6t^2 + 25t^4) k ^{\to}}$

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2 years ago

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Answer:

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Step-by-step explanation:

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