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2 years ago

6

Write 1.6 x 10 in standard form.

2 answers:

ddd [48]2 years ago

8 0

The answer is 16000000000.
Because you take the decimal and move it 10 times to the right.

Bas_tet [7]2 years ago

3 0

Answer:

$1.6 \times 10 = 16 \\$

To multiply a decimal by 10, move the decimal point in the multiplicant by one place to the right. Here we multiplied the number 1.6 by 10 so we move 1 place to the right.

To multiply a decimal by 100, move the decimal point in the multiplicant by two places to the right.

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Ms.Ambrose paid $10 for 1.25 pounds of almonds. How much did the almost cost per pound

love history [14]

Answer:

A

Step-by-step explanation:

10 divided by 1.25=8

7 0

3 years ago

Read 2 more answers

The slope of the lines that passes through the points (-10,0) and (-13,3)

goldenfox [79]

Answer:

-1

Step-by-step explanation:

The formula to find the slope of a line is:

$\frac{y_{2}- y_{1} }{x_{2} -x_{1} }$

where (x1, y1) and (x2, y2) are points on the line. We can substitute the points (-10, 0) and (-13, 3) into the formula and simplify:

$\frac{3-0}{-13-(-10)} =\frac{3}{-13+10} =\frac{3}{-3} =-1$

This means the slope of the line is -1.

4 0

2 years ago

What is the measure of angle TSU?

Elden [556K]

Answer:

63°

Step-by-step explanation:

TSU = 180 - 117 = 63

6 0

3 years ago

Read 2 more answers

Find S12 for geometric series: (-7.5) + 15 + (-30) + ...

kolezko [41]

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

$(-7.5) + 15 + (-30) + ...$

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

$a_n=a_1\cdot r^{n-1}$

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2$

$\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$r=-2$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=\left(-7.5\right)$

$a_n=a_1\cdot r^{n-1}$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=\left(-7.5\right)\left(-2\right)^{n-1}$

$a_n=-\left(-2\right)^{n-1}\cdot \:7.5$

$\mathrm{Geometric\:sequence\:sum\:formula:}$

$a_1\frac{1-r^n}{1-r}$

$\mathrm{Plug\:in\:the\:values:}$

$n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2$

$=\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}$

$=-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}$

$\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$=-\frac{-30712.5}{1+2}$ ∵ $\left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5$

$=-\frac{-30712.5}{3}$

$=\frac{30712.5}{3}$

$=10237.5$

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

5 0

3 years ago

The volume of a sphere is two-thirds of a cylinder. What is the volume of a cylinder that has the same diameter as a sphere with

sattari [20]

Answer:

$V_2= \frac{28}{3} u^3$

Step-by-step explanation:

Given

Represent the volume of the cylinder with V1 and the volume of the sphere with V2

So, from the first statement: we have:

$V_2 =\frac{2}{3}V_1$

and

$V_1 = 14u^3$

To solve for $V_2$ , we simply substitute $14u^3$ for $V_1$ in $V_2 =\frac{2}{3}V_1$

$V_2 =\frac{2}{3}V_1$

$V_2= \frac{2}{3} * 14u^3$

$V_2= \frac{2* 14}{3} u^3$

$V_2= \frac{28}{3} u^3$

Hence, the volume of the sphere is $\frac{28}{3} u^3$

5 0

2 years ago