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3 years ago

10

Slope -2/3 .x-intercept at 3 written in y=mx+b

1 answer:

siniylev [52]3 years ago

5 0

Given the slope, m = -2/3, and the x-intercept, (3,0):

Use these values and plug into the slope-intercept form to solve for the y-intercept, b:

y = mx + b

0 = -2/3(3) + b

0 = -2 + b

Add 2 to both sides to isolate b:

0 + 2 = -2 + 2 + b

2 = b

Now that we have our slope, m = -2/3, and the y-intercept, 2

The linear equation in slope-intercept form is:

y = -2/3x + 2

Please Mark my answers as the Brainliest, if you find this helpful :)

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Step-by-step explanation:

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(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

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The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: $x + y \le 4$ ) are:

$(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)$

n(A)=15

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