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WITCHER [35]
3 years ago
10

Slope -2/3 .x-intercept at 3 written in y=mx+b

Mathematics
1 answer:
siniylev [52]3 years ago
5 0
Given the slope, m = -2/3, and the x-intercept, (3,0):

Use these values and plug into the slope-intercept form to solve for the y-intercept, b:

y = mx + b

0 = -2/3(3) + b

0 = -2 + b

Add 2 to both sides to isolate b:

0 + 2 = -2 + 2 + b

2 = b

Now that we have our slope, m = -2/3, and the y-intercept, 2

The linear equation in slope-intercept form is:

y = -2/3x + 2


Please Mark my answers as the Brainliest, if you find this helpful :)
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Airida [17]
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so

IKJ
ok so we see that we have a triangle
to find the internal angles (which add to 180)
we do, opposite angles are equal
JIK=59
also CJI+KJI=180 so 132+KJI=180, KJI=48
so
59+48+IKJ=180
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HIB
we can assume that AB is paralell to CD
so therefor IJK=HIB=48 (from previous question)

EIJ is adding to EIH to get 180
EIJ+59=180
EIJ=121

AIK=AIJ+JIK
JIK=59
AIJ=HIB=48
AIK=59+48=107


IKJ=73
HIB=48
EIJ=121
AIK=107
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