Answer:
-2 ≥ b
Step-by-step explanation:
10 ≤ -2 ( 9 + 12b ) / 3
10 ≤ -2 ( 3 + 4b )
-10 ≥ 2 ( 3 + 4b )
-10 ≥ 6 + 8b
-16 ≥ 8b
-2 ≥ b
Answer:
We have;
7 pencil boxes and 5 eraser boxes
Step-by-step explanation:
To find the smallest number of boxes that can be bought, what we simply do is to find the lowest common multiple of the content of each of the boxes
hence, we are going to find the lowest common multiple of 10 and 14
The lowest common multiple of 10 and 14 is 70
So the smallest number of pencil boxes that can be bought is 70/10 = 7
The smallest number of eraser boxes would be 70/14 = 5
P should equal 3. hope this helps.
