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77julia77 [94]
3 years ago
9

I need to get a good score! plss help!!!!

Mathematics
2 answers:
lesya [120]3 years ago
7 0

Answer:

82 is your answer

Step-by-step explanation:

3x6 = 18

8x8=64

18+64=82

never [62]3 years ago
4 0

Answer:

82 m²

Step-by-step explanation:

The blue figure is composed of a square ( on the right ) and a rectangle on the upper left )

Area of blue figure is the sum of the 2 areas , that is

Area = (8 × 8) + (6 × 3) = 64 + 18 = 82 m²

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Jamar earned $2,500 from his summer job. This is 350 more than twice what his friend Todd earned. Please write the equation for
cluponka [151]
2500 = 2x + 350
2500 - 350 = 2x
2150 = 2x
2150/2 = 2x/2
1025 = x
x = $ Todd had earned
5 0
3 years ago
How can i find this answer ?
Furkat [3]
19-2x=3x-16

19+16=3x+2x

5x=35

Therefore, x=7.

19-2x=3x-16

19+16=3x+2x

5x=35

Therefore, x=7.

As angle /_ABC is 19-2x,

angle /_ABC is 19-2(7)=5.
8 0
3 years ago
Read 2 more answers
12 + 1/5 (10x + 5) =59
nordsb [41]

Answer: Is the answer 59

5 0
3 years ago
Paul starts from his house and bikes 30 miles east, then 20 miles south. How much farther south must Paul bike to be 50 miles aw
padilas [110]
30 miles long

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5 0
3 years ago
Part 3: Use the information provided to write the standard form equation of each circle
Ber [7]

Answer:

9. \displaystyle (x - 7)^2 + (y - 15)^2 = 25

8. \displaystyle (x - 1)^2 - (y - 10)^2 = 49

7. \displaystyle (x + 5)^2 + (y + 19)^2 = 9

Step-by-step explanation:

\displaystyle [x - h]^2 - [y - k]^2 = r^2 → Hyperbola\:Equation \\ [x - h]^2 + [y - k]^2 = r^2 → Circle\:Equation \\ [h, k] → Centre

According to the equations in the exercises, in the parentheses, ALL NEGATIVE SIGNS give the OPPOSITE terms of what they REALLY are, so be EXTREMELY CAREFUL with your translations:

9. [4, 11]

+ 3 + 4

_____

[7, 15] → (x - 7)² and (y - 15)²

8. [−2, 8]

+ 3 + 2

_____

[1, 10] → (x - 1)² and (y - 10)²

7. [−8, −14]

+ 3 - 5

______

[−5, −19] → (x + 5)² and (y + 19)²

** NOTISE THAT THE RADII <em>NEVER</em><em> </em>ALTER.

I am joyous to assist you anytime.

4 0
3 years ago
Read 2 more answers
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