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11111nata11111 [884]
3 years ago
15

X^4 y^6 x^-2 ———————- Y^3 y^2 x^8

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

y^1 / x^4

Step-by-step explanation:

Formulas : -

p^q / p^r = p^( q - r )

p^q . p^r = p^( q + r )

p^-q = 1 / p^q

x^4 y^6 x^-2

------------------

y^3 y^2 x^8

= x^4 y^6 x^-2

------------------

y^3 y^2 x^8

= x^4 x^-2 y^6

------------------

y^3 y^2 x^8

= x^( 4 + ( - 2 ) ) y^6

-------------------------

y^( 3 + 2 ) x^8

= x^( 4 - 2 ) y^6

------------------

y^5 x^8

= x^2 y^6

------------------

x^8 y^5

= x^( 2 - 8 ) y^( 6 - 5 )

= x^-4 y^1

= y^1 / x^4

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