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3 years ago

If x < 0, y > 0, and x + y = z, which statement about z is true?

Mathematics

1 answer:

vivado [14]3 years ago

7 0

Answer:

Z is greater than zero because it equals 1 or more.

Step-by-step explanation:

X/Y/Z=1+

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AURORKA [14]

GET THEM ALL RIGHT!?

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3 years ago

Write an equation of the line with a slope of and y-intercept of -8.

S_A_V [24]

y= mx+b

slope is also m= 0

b is the y-intercept=-8

answer:

y= -8

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3 years ago

What are the zeros of the polynomial function

solniwko [45]

Option B

The zeros of the polynomial function are x = 0 , x = 6, x = -1

Solution:

Given function is:

$f(x) = x^3 -5x^2 - 6x$

To find: zeros of the polynomial function

To find the zeros of polynomial function, set the function equal to zero and then solve for x.

$x^3 -5x^2 - 6x = 0$

Taking "x" as common term, we get

$x(x^2 - 5x - 6) = 0$

Equating to zero,

$x = 0 \text{ and } x^2 - 5x - 6 = 0$

So one of the zeros of polynomial is x = 0

Let us solve $x^2 - 5x - 6 = 0$ to find other zeros

Let us solve using quadratic formula,

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{ for } x^2 - 5x - 6 = 0 \text{ we have } a = 1 ; b = -5 ; c = -6$

$\text{ The discriminant } b^2 - 4ac > 0 , \text{ so, there are two real roots }$

Substituting the values of a, b, c in above formula,

$x=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2(1)}\\\\x=\frac{5 \pm \sqrt{25+24}}{2}=\frac{5 \pm \sqrt{49}}{2}\\\\x=\frac{5 \pm 7}{2}\\\\x=\frac{5+7}{2} \text{ or } x=\frac{5-7}{2}\\\\x=\frac{12}{2} \text{ or } x=\frac{-2}{2}\\\\x=6 \text{ or } x=-1$