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DerKrebs [107]
3 years ago
7

I WILL MAKE BRAINLIEST, if any scamed I will Report him.

Physics
2 answers:
antiseptic1488 [7]3 years ago
5 0

Answer:

1N of force is exerted onto the object.

Hope this helps :)

marusya05 [52]3 years ago
4 0
1N of force. BTW, don’t just use “him” females and people of other genders can answer here too, please be inclusive and respectful.
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If τ=r×F then F.τ is equal
Mademuasel [1]
Yes that is correct.
4 0
3 years ago
Which statements best describe half-lives of radioactive isotopes? Check all that apply.
victus00 [196]

Answer:

A

Explanation:

half life is the time taken for a radioactive isotopes to dissociate

7 0
2 years ago
How many electrons does it take to make up 4.33 C of charge?
Dovator [93]

Answer:

Number of electrons, n=2.7\times 10^{19}

Explanation:

It is given that,

Charge, q = 4.33 C

We need to find the number of electrons that make 4.33 C of charge. According to quantization of charge as :

q=ne

n = number of electrons

e = electron's charge

n=\dfrac{q}{e}

n=\dfrac{4.33\ C}{1.6\times 10^{-19}\ C}

n=2.7\times 10^{19}

So, the number of electrons are 2.7\times 10^{19} Hence, this is the required solution.  

7 0
3 years ago
Find the sum of the vectors: 40m/s2 Northeast, 10 m/s2 Northeast
podryga [215]

Answer:

Explanation:

Since both vectors are pointing on the same direction (Northeast), the sum of them will point in that same direction, and its magnitud will be the sum of the magnitudes of each vector (40m/s2+10m/s2). This problem is just a problem in one dimension. The sum of the vectors is then 50m/s2 Northeast.

8 0
3 years ago
Which condition is required for Coulomb's law to hold true?
AleksAgata [21]
The correct answer is:
<span>Point charges must be in a vacuum.

In fact, the usual form for of the Coulomb's law is:
</span>F= \frac{1}{4 \pi \epsilon_0}  \frac{q_1 q_2}{r^2}
<span>where
</span>\epsilon_0 is the permittivity of free space
<span>q1 and q2 are the two charges
q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>F= \frac{1}{4 \pi \epsilon_0 \epsilon_r} \frac{q_1 q_2}{r^2}
where \epsilon_r is the relative permittivity, which takes into account the dielectric effects of the material.
7 0
3 years ago
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