A man (mass=68 kg) on a parachute is falling at terminal velocity (v=59 m/s)

Physics

1 answer:

raketka [301]3 years ago

3 0

Explanation:

It is given that,

Mass of the man, m = 68 kg

Terminal velocity of the man, v = 59 m/s

We need to find the rate at which the internal energy of the man and of the air around him increase. The gravitational potential energy of the man is given by :

$E=mgh$

Differentiating equation (1) wrt t as :

$\dfrac{dE}{dt}=mg\dfrac{dh}{dt}$

Since, $v=\dfrac{dh}{dt}=59\ m/s$

$\dfrac{dE}{dt}=68\times 9.8\times 59$

$\dfrac{dE}{dt}=39317.6\ J/s$

So, the internal energy of the man and the air around him is increasing at the rate of 39317.6 J/s. Hence, this is the required solution.

You might be interested in

The cartesian coordinates of a point in the xy plane are x = −6.46 m, y = −3.78 m. Find the distance r from the point to the ori

11111nata11111 [884]

Explanation:

Use Pythagorean theorem:

r² = x² + y²

r² = (-6.46 m)² + (-3.78 m)²

r = 7.48 m

5 0

3 years ago

A clinical psychologist is one type of pure basic research psychologist . True are false

adoni [48]

false. clinical deals with patients and treats the.

research looks at root causes which clinical applies

8 0

3 years ago

Describe Kinetic Energy.

mina [271]

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body when decelerating from its current speed to a state of rest.