Answer:
5.7058kj/mole
Explanation:
Please see attachment for step by step guide
Answer:
A cost is something you have to give up or sacrifice and a benefit is something that is gained or is helpful.
Explanation:
In a cost-benefit analysis of a system, an engineer is to simply look at the requirements for the system and determine the costs to build the system, both in financial value and energy value. Additionally, the engineer needs to determine the benefits that would come from choosing a particular path of cost. If the benefits outweigh the cost for the project, then the solution is accepted. Else, the cost outweighs the benefit and the solution is rejected.
Is this even a real question?
Solar time for
North Platte is 13.02
Boise is 13.02
Eastern daylight time is 12.48
Central daylight is 12.06
<u>Explanation:</u>
- 6 hours "central standard time" is the standard time zone. The saving time of daylight is + 1 hour. current time zone is the 5 hours central daylight time.
- 7 hours is the mountain standard time. The saving time of daylight is + 1 hour. current time zone is the 6 hours central daylight time.
- 5 hours is the eastern daylight time. The time shifts to +1 hour forwarded to eastern daylight zone and GMT is behind 4 hours.
- 5 hours is the central daylight time. The GMT is behind 5 hours during summer season
Answer:
The solution is written in Python
- binary = ""
- decimal = 13
- quotient = int(decimal / 2)
- remainder = decimal % 2
- binary = str(remainder) + binary
-
- while(quotient >0):
- decimal = int(decimal / 2)
- quotient = int(decimal / 2)
- remainder = decimal % 2
- binary = str(remainder) + binary
-
- print(binary)
Explanation:
Firstly, we declare a variable <em>binary</em> and initialize it with an empty string (Line 1). This <em>binary </em>is to hold the binary string.
Next, we declare variable <em>decimal, quotient </em>and<em> remainder </em>(Line 2-4). We assign a test value 13 to decimal variable and then get the first quotient by dividing decimal with 2 (Line 3). Then we get the remainder by using modulus operator, % (Line 4). The first remainder will be the first digit joined with the binary string (Line 5).
We need to repeat the process from Line 3-5 to get the following binary digits. Therefore create a while loop (Line 7) and set a condition that if quotient is bigger than 0 we keep dividing decimal by 2 and calculate the quotient and remainder and use the remainder as a binary digit and join it with binary string from the front (Line 9-11).
At last, we print the binary to terminal (Line 13).