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3 years ago

5

Identify renewable energy sources you will propose. Explain the key elements to your solution and the basic technical principles

involved.

1 answer:

MArishka [77]3 years ago

3 0

Answer:

A renewable electricity generation technology harnesses a naturally existing energy. But they have other features that a few fringe customers value.

Explanation:

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Air initially at 15 psla and 60 F is compressed to 75 psia and 400 F. The power input to air under steady state condition is 5 h

Triss [41]

Answer: $\dot{m}=3.46lbm/min$

Explanation:

Initial conditions

$P_1=15 psia$

$T_1=60 F^{\circ}$

Final conditions

$P_2=75 psia$

$T_2=400F^{\circ}$

Steady flow energy equation

$\dot{m}\left [ h_1+\frac{v_1^2}{2}+gz_1\right ]+\dot{Q}=\dot{m}\left [ h_2+[tex]\frac{v_2^2}{2}+gz_2\right ]+\dot{W}$

$\dot{m}\left [ c_pT_1+\frac{0^2}{2}+g0\right ]+\dot{Q}=\dot{m}\left [ c_pT_2+\frac{0^2}{2}+g0\right ]+\dot{W}$

$\dot{m}c_p\left [ T_1-T_2\right ]+\left [ -5hp\right ]=\dot{W} -5\times 746\times 3.4121$

$-4\dot{m}-\dot{m}\times 0.24\times \left [ 400-60\right ]$

$-81.6\dot{m}-4\dot{m}=-4.949 BTU/sec$

$\dot{m}=0.057821lbm/sec$

$\dot{m}=3.46lbm/min$

3 0

3 years ago

Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 85 vol% carbide

velikii [3]

Answer:

Explanation:

k_max = 26.9 w/mk

k_min = 22.33 w/mk

Explanation:

a) the maximum thermal conductivity is given as

K_MAX = k_m v_m + k_p v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.15

v_p = proportion of carbide in the cement = 0.85

$K_MAX = k_m v_m + k_p v_p$

= 66*0.15 + 20*0.85

k_max = 26.9 w/mk

b) the minimum thermal conductivity is given as

$k_min = \frac{ k_{carbide} *k_{metal}}{k_{metal} v_{carbide} +k_{carbide} v_{metal}}$

= \frac{20*66}{20*0.15 +66*0.85}

k_min = 22.33 w/mk

5 0

3 years ago

Relevance of engineering law and ethic in contemporary society

baherus [9]

Answer:

Engineering law and ethics are the moral codes associated with the field in which engineers are meant to adhere strictly to.

These ethics help in the safety of the engineers as a result of wearing protective clothing being a part of the ethics . Accuracy should also be taken important in research and daily activities. Corrupt practices and activities which poses risk to the environment is also strictly prohibited.

7 0

4 years ago

The input shaft to a gearbox rotates at 2300 rpm and transmits a power of 42.6 kW. The output shaft power is 34.84 kW at a rotat

Marrrta [24]

Answer:

Torque at input shaft will be 176.8695 N-m

Explanation:

We have given input power $P_{IN}=42.6KW=42.6\times 10^3W$

Angular speed = 2300 rpm

For converting rpm to rad/sec we have multiply with $\frac{2\pi }{60}$

So $2300rpm=\frac{2300\times 2\pi }{60}=240.855rad/sec$

We have to find torque

We know that power is given by $P=\tau \omega$ , here $\tau$ is torque and $\omega$ is angular speed

So $42.6\times 10^3=\tau \times 240.855$

$\tau =176.8695N-m$

So torque at input shaft will be 176.8695 N-m

4 0

4 years ago

For a steel alloy it has been determined that a carburizing heat treatment of 14 h duration at 809°C will raise the carbon conce

Yakvenalex [24]

Answer:

$t_2 = 27.7 hr$

Explanation:

Given data:

carbon concentration = 0.54%

from the relation given below calculate the time required to achieve concentration at 6.00 mm from surface

$\frac{x^2}{Dt} = constant$

D considered constant

$\frac{x^2}{t} = constant$

here, x POSITION FROM SURFACE, t is time required to achieve concentration

$\frac{x_1^2}{t_1} = \frac{x_2^2}{t_2}$

$\frac{3.6^2}{14} = \frac{6^2}{t_2}$

$t_2 = 27.7 hr$

3 0

4 years ago