3 years ago

Wn sóiEoEfind the transfer function

Engineering

1 answer:

zaharov [31]3 years ago

8 0

Kamwiisyveu ajoae iosiwnjije j’dis ke si

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A 400 kg machine is placed at the mid-span of a 3.2-m simply supported steel (E = 200 x 10^9 N/m^2) beam. The machine is observe

Alenkinab [10]

Answer:

moment of inertia = 4.662 * 10^6 $mm^4$

Explanation:

Given data :

Mass of machine = 400 kg = 400 * 9.81 = 3924 N

length of span = 3.2 m

E = 200 * 10^9 N/m^2

frequency = 9.3 Hz

Wm ( angular frequency ) = 2 $\pi f$ = 58.434 rad/secs

also Wm = $\sqrt{\frac{g}{t} }$ ------- EQUATION 1

g = 9.81

deflection of simply supported beam

t = $\frac{wl^3}{48EI}$

insert the value of t into equation 1

W $m^2$ = $\frac{g*48*E*I}{WL^3}$ make I the subject of the equation

I ( Moment of inertia about the neutral axis ) = $\frac{WL^3* Wn^2}{48*g*E}$

I = $\frac{3924*3.2^3*58.434^2}{48*9.81*200*10^9}$ = 4.662 * 10^6 $mm^4$

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Motorcycles are extremely hard to see if they are _______. powered by quiet motors approaching from the side driving on the shou

Assoli18 [71]

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3 years ago

Who invented engineering first?

astra-53 [7]

Explanation:

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3 years ago

Car A starts from rest at t = 0 and travels along a straight road with a constant acceleration of 6 ft/s2 until it reaches a spe

taurus [48]

The distance traveled by car A when they pass each other is 1071m

<h3>Calculations and Parameters</h3>

Given:

t=0

constant acceleration= 6 ft/s^2

speed= 80 ft/s^2

$S_A= \frac{at1^2}{2} + V_At\\S_B= V_B (t1 +t)$

= $2 * (\frac{27}{2})^{2}/2 + 27 * 32.9$

= 1071m

Wn sóiEoEfind the transfer function​

Wn sóiEoEfind the transfer function