R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
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Answer:
a)
The crack and connecting rod is used in the design of car.This mechanism is known as slider -crank mechanism.
Components:
1.Inlet tube
2. Wheel
3. Exhaust
4. Engine
5.Air tank
6.Pressure gauge
7.Stand
8. Gate valve
b)
The efficiency of air engine is less as compare to efficiency of electric engine and this is not ecofriendly because it produce green house gases.These gases affect the environment.
c)
it can run around 722 km when it is full charge.
Answer:
Stress corrosion cracking
Explanation:
This occurs when susceptible materials subjected to an environment that causes cracking effect by the production of folds and tensile stress. This also depends upon the nature of the corrosive environment.
Factors like high-temperature water, along with Carbonization and chlorination, static stress, and material properties.
Answer:
they are used for electrical currents so that they can flow along the appropriate wires in the circuit
Explanation:
Its 0.001
0.01 x100 = 1mm
0.001x100=0.1mm
0.1=10mm
1m
