<span>BaCl2+Na2SO4---->BaSO4+2NaCl
There is 1.0g of BaCl2 and 1.0g of Na2SO4, which is the limiting reagent?
"First convert grams into moles"
1.0g BaCl2 * (1 mol BaCl2 / 208.2g BaCl2) = 4.8 x 10^-3 mol BaCl2
1.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 7.0 x 10^-3 mol Na2SO4
(7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2 ) = 1.5 mol Na2SO4 / mol BaCl2
"From this ratio compare it to the equation, BaCl2+Na2SO4---->BaSO4+2NaCl"
The equation shows that for every mol of BaCl2 requires 1 mol of Na2SO4. But we found that there is 1.5 mol of Na2SO4 per mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
Answer:
A
Explanation:
because if you bond postitive and positive they would repell
Answer:
62.586 gram
Explanation:
moles of Al(OH)3 = mass / molar mass = 35.1 / (27+17x3) = 0.45 mol
moles of H2SO4 = mass / molar mass = 53.94 / (2+32+16x4) = 0.55 mol
H2SO4 is the limiting reagent (reacts completely)
⇒ moles of Al2(SO4)3 is worked out by moles of H2SO4
moles of Al2(SO4)3 = moles of H2SO4 / 3 = 0.183 mol
mass of Al2(SO4)3 = mole x molar mass = 0.183 x (27x2 + 96x3) = 62.586 gram
Nucleic Acids, Protein Coat,and Lipid Membrane
