Answer:
4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.
Explanation:
Half life (t1/2) = 8 days
Original mass (No) = 64 g
Elapsed time (t) = 32 days
Mass remaining (Nt) = ?
Using the half life equation we can obtain the mass remaining (Nt)
Nt = No (1/2) ^t/t1/2
Substituting the values, we have;
Nt = 64 * ( 1/2 ) ^32/8
Nt = 64 * (1/2) ^4
Nt = 64 * 0.0625
Nt = 4 g
So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.
Covalent compounds do not conduct electric current in a water solution well because they do not dissociate into ions.
Answer:
(215 torr)(51 mL)=("x" torr)(18,500 mL) x = O.593 torr
The smallest observable object for an electron microscope is 6.6nm.
<h3>Calculation of smallest observable object for an electron microscope :</h3>
Given,
Speed of electron (u) = 5.5 x 10⁴ m/s
De Broglie's formula,
wavelength, λ =h/mu
where,
h = Planck's constant = 6.626 x
Js
m = mass of electron, 9.11 x
kg
λ =h/mu
= 6.626 x
Js /9.11 x
kg x 5.5 x 10⁴ m/s
= 0.132 x
m
= 13.2 x
m
It is well known that the smallest thing that can be observed under any microscope is identical to the radiation's wavelength for the smallest object that can be seen under an electron microscope.
Therefore, 13.2 x
m/2
= 6.6 x
m
= 6.6 nm
Hence, the smallest observable object for an electron microscope is 6.6nm.
Learn more about electron microscope here:
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I think it is mold or molehill one of two