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Firdavs [7]
3 years ago
5

7. How many protons are in 1.9 mol of Uranium?

Chemistry
1 answer:
Anna [14]3 years ago
5 0

Answer:

92 im not really sure

Explanation:

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10. (a) Describe how the structure of an alloy is different to a pure metal
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5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2

Help
4 0
3 years ago
A protein denatures when you cook it at 60°C. What is that temperature on the
seropon [69]

Answer:

333K

Explanation:

Answer is actually 333.15, but to round it off, is 333

7 0
3 years ago
Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to
jenyasd209 [6]
<span>5.45 x 10^3 kg of sodium carbonate is needed to neutralize 5.04 kg of sulfuric acid. For this, I will assume you have pure H2SO4. So first, you need to calculate the molar mass of H2SO4 and Na2CO3. Lookup the atomic weights of all the elements involved. Atomic weight of Sodium = 22.989769 Atomic weight of Sulfur = 32.065 Atomic weight of Carbon = 12.0107 Atomic weight of Oxygen = 15.999 Atomic weight of Hydrogen = 1.00794 Molar mass of H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass of Na2CO3 = 2 * 22.989769 + 12.0107 + 3 * 15.999 = 105.987238 g/mol The balanced equation for the reaction of Na2CO3 with H2SO4 is Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O so for every mole of sulfuric acid to be neutralized, you need 1 mole of sodium carbonate. You can determine the number of moles of sulfuric acid you have and then calculate the mass of that many moles of sodium carbonate. But, there's an easier way. Just use the relative mass differences between sodium carbonate and sulfuric acid. So 105.987238 g/mol / 98.07688 g/mol = 1.080655 So that means for every kg of sulfuric acid, you need 1.080655 kg of sodium carbonate. Now do the multiplication. 5.04 x 10^3 kg * 1.080655 = 5.4465 x 10^3 kg. Since you only have 3 significant figures for your data, round the result to 3 significant figures, giving 5.45 x 10^3 kg</span>
3 0
3 years ago
What is the energy of a photon that has a wavelength of 8.6x10^3nm?
aniked [119]

Answer:

The energy of the photon is 2.311\times 10^{-20}\ J.

Explanation:

Given:

The wavelength of the photon is given as:

\lambda =8.6\times 10^3\ nm\\1\ nm = 10^{-9}\ m\\\therefore \lambda = 8.6\times 10^{3}\times 10^{-9}=8.6\times 10^{-6}\ m

The energy of a photon in terms of its wavelength is given as:

E_p=\frac{hc}{\lambda}\\Where,\ h\rightarrow \textrm{Planck's constant}=6.626\times 10^{-34}\ Js\\c\rightarrow \textrm{velocity of light}=3\times 10^8\ m/s

Plug in all the given values and calculate energy of the photon, E_p. This gives,

E_p=\frac{6.626\times 10^{-34} \times 3\times 10^8}{8.6\times 10^{-6}}\\E_p=\frac{19.878\times 10^{-26}}{8.6\times 10^{-6}}\\E_p=2.311\times 10^{-20}\ J

Therefore, the energy of the photon is 2.311\times 10^{-20}\ J.

3 0
4 years ago
3) Which element is the 2s orbital closest to the nucleus?
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