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kherson [118]
3 years ago
6

HELP!! what are the usual products of combustion reactions?

Chemistry
2 answers:
kotykmax [81]3 years ago
8 0

Answer:

The usual products of combustion reactions are carbon dioxide and water.

Explanation:

Combustion reaction is when a substance reacts with oxygen gas, resulting in a release of energy in the form of light and heat. Combustion reactions must have oxygen (O2) as one of the reactants.

Alekssandra [29.7K]3 years ago
5 0

Explanation:

Carbon dioxide and water

I hope it helps

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The gases inside of a normal tire are usually measured when they are at ambient standard temperature (298 K) & under a contr
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Answer:

100°C

Explanation:

The following were obtained from the question:

Initial temperature (T1) = 298 K

Initial pressure (P1) = 32.5 Psi

Final pressure (P2) = 40.68 Psi

Final temperature (T2) =..?

The final temperature can be obtained as follow:

P1/T1 = P2/T2

32.5/298 = 40.68/T2

Cross multiply to express in linear form

32.5 x T2 = 298 x 40.68

Divide both side by 32.5

T2 = (298 x 40.68) /32.5

T2 = 373K

Next, we shall convert 373K to celsius.

This is illustrated below:

T(°C) = T(K) – 273

T(K) = 373

T(°C) = 373 – 273

T(°C) = 100°C

Therefore, the temperature of the air inside the tire at 40.68 Psi is 100°C

8 0
4 years ago
4 Nitrogen monoxide reacts with oxygen like this:
olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

a.

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

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b.

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3

c.

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

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