Hi there!
f(x) = 2(1/5)ˣ
Recall the form of an exponential function:
f(x) = a(b)ˣ where:
a = initial value
b = rate of decay/growth
If b > 1, the function is undergoing exponential growth. If b < 1, then the function is undergoing exponential decay.
1/5 < 1, so the function is undergoing exponential decay, not growth.
Answer:
See proof below
Step-by-step explanation:
An equivalence relation R satisfies
- Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
- Symmetry: For all x,y, if xRy then yRx.
- Transitivity: For all x,y,z, If xRy and yRz then xRz.
Let's check these properties: Let x,y,z be bit strings of length three or more
The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.
If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.
If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.
N(1/5) = (2/15)
divide both sides by (1/5)
n = (2/15)/(1/5)
to divide fractions, cross multiply, e.g. (2*5)/(15*1) = 10/15
n = 10/15 = 2/3 or 0.666666.
The answer is the last one. Except for the first one, the questions are asking which two line segments are congruent (or equal to each other) in the triangle. Hope this helps :3<span />
